Default access modifier in C#

问题:

If I will create a new object like the following, which access modifier will it have by default?

Object objectA = new Object();

回答1:

Any member will always have the most restrictive one available - so in this case the accessibility of objectA is private. (Assuming it's an instance variable. It makes no sense as a local variable, as they don't have any access rules as such.)

So this:

class Foo
{
    Object objectA = new Object();
}

is equivalent to this:

internal class Foo
{
    private Object objectA = new Object();
}

The "default to most private" means that for types, the accessibility depends on the context. This:

class Outer
{
    class Nested
    {
    }
}

is equivalent to this:

internal class Outer
{
    private class Nested
    {
    }
}

... because you can't have a private non-nested class.

There's only one place where adding an explicit access modifier can make something more private than it is without, and that's in property declarations:

public string Name { get; set; } // Both public

public string Name { get; private set; } // public get, private set

回答2:

void Foo()
{
    // private in method scope
    Object objectA = new Object();
}

class Bar()
{
    // private in class scrope
    Object objectA = new Object();
}

回答3:

It is private by default.

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回答4:

As a class member: private.

If it's a local variable declared within the body of a method, it has no accessibility outside that method. But I'm guessing you already knew that.

回答5:

For class members and struct members, including nested classes and structs, private is the default.

For classes and structs - internal is the default

You can check out MSDN for further reading..

回答6:

The class/type itself will default to "internal". The object you create will default to "private".

回答7:

Classes and structs are declared as internal by default!

Read more here

回答8:

The access specifier of class is internal.

The access specifier of a variable is private.