Listview Large Icon right click to open ContextMen

问题:

In my project I have a ListView and I would like to open my ContextMenuStrip when I clicked right button in the large icon. I tried many things but I am unsuccessful. When I right click inside of ListView the ContextMenuStrip opens, but I want to see just when I right clicked the large icon.

Also I need to help about get the clicked icon's name (properties).

回答1:

This is a quick and dirty solution; please do put more work into it than I did..

// a class level reference, prepare it where you want..
ContextMenuStrip ms = new ContextMenuStrip();

You should either code the MouseDown or the MouseUp event:

private void listView1_MouseDown(object sender, MouseEventArgs e)
{
    // disassociate from listview at first:
    listView1.ContextMenuStrip = null;

    // check for right button
    if (e.Button != System.Windows.Forms.MouseButtons.Right) return;

    // get item info:
    ListViewHitTestInfo hi = listView1.HitTest(e.Location);

    // no item hit:
    if (hi.Item == null) return;

    // calculate the image rectangle:

    // this contains the unscrolled y coordinate:
    Point iloc = listView1.GetItemRect(hi.Item.Index).Location;
    // we combine it with the x-position:
    Rectangle r = new Rectangle(new Point (hi.Item.Position.X,  iloc.Y),
                                imageList1.ImageSize);
    // no image hit:
    if ( !r.Contains(e.Location) ) return;

    // maybe prepare or change the menue now..
    // here I display the image name from the keys array:
    ms.Items[0].Text = imageList1.Images.Keys[hi.Item.ImageIndex];
    ms.Location = e.Location;

    // associate with listview and show
    listView1.ContextMenuStrip = ms;
    ms.Show();
}

回答2:

Can you please try the following and let see wether it works or not... private void listView1_MouseClick(object sender, MouseEventArgs e) {
if (e.Button == MouseButtons.Right) { if (listView1.FocusedItem.Bounds.Contains(e.Location) == true) { contextMenuStrip1.Show(Cursor.Position); } }
}

回答3:

This should work

private void listView1_MouseClick(object sender, MouseEventArgs e) { ListView listView = sender as ListView; if (e.Button == System.Windows.Forms.MouseButtons.Right) { ListViewItem item = listView.GetItemAt(e.X, e.Y); if (item != null) { item.Selected = true; contextMenuStrip1.Show(listView , e.Location); } } }

Search the listview item on mouse click location. If it is there, show the menu.........