I'm trying a long time to remove duplicate from a list and create a dictionary with keys like php (0,1,2....).
I have tried :
ids = dict(set([1,2,2,2,3,4,5,4,5,6]))
print ids
Then I want to
for key, value in ids.iteritems():
#stuff
Of course I get the following error because ids is not a dictionary:
TypeError: cannot convert dictionary update sequence element #0 to a sequence
Thanks!
Edit:
I think my data was a bit misleading:
I have a list: [foo, bar, foobar, barfoo, foo, foo, bar]
and I want to convert it to: { 1: 'foo', 2 : 'bar', 3 : 'foobar', 4: 'barfoo'}
I don't mind about shorting.
To turn your set of values into a dictionary with ordered 'keys' picked from a sequence, use a defaultdict
with counter to assign keys:
from collections import defaultdict
from itertools import count
from functools import partial
keymapping = defaultdict(partial(next, count(1)))
outputdict = {keymapping[v]: v for v in inputlist}
This assigns numbers (starting at 1) as keys to the values in your inputlist, on a first-come first-serve basis.
Demo:
>>> from collections import defaultdict
>>> from itertools import count
>>> from functools import partial
>>> inputlist = ['foo', 'bar', 'foobar', 'barfoo', 'foo', 'foo', 'bar']
>>> keymapping = defaultdict(partial(next, count(1)))
>>> {keymapping[v]: v for v in inputlist}
{1: 'foo', 2: 'bar', 3: 'foobar', 4: 'barfoo'}
Not sure what you intend to be the values associated with each key from the set
.
You could use a comprehension:
ids = {x: 0 for x in set([1,2,2,2,3,4,5,4,5,6])}
You may use zip for this.
Sample code
>>> ids
['foo', 'bar', 'foobar', 'barfoo', 'foo', 'foo', 'bar']
>>> dict(zip(range(1,len(ids)+1), sorted(set(ids))))
{1: 'bar', 2: 'barfoo', 3: 'foo', 4: 'foobar'}
>>>
If you want to start the key with 0, then Aya's soultion is better.
>>> ids
['foo', 'bar', 'foobar', 'barfoo', 'foo', 'foo', 'bar']
>>> dict(enumerate(sorted(set(ids))))
{0: 'bar', 1: 'barfoo', 2: 'foo', 3: 'foobar'}