How to rename all columns in a dataframe to includ

问题:

I have a list of data frames listofdfs. To rename the columns of one of the dataframes singledf in the list, the following code works:

colnames(listofdfs[["singledf"]]) <- paste(colnames(listofdfs[["singledf"]]), "singledf")

Aim

To rename all columns for all data frames in a list of dataframes, listofdfs, to include the name of the dataframe in all of the respective column names.

Attempt 1

for (i in listofdfs){
        colnames(listofdfs[i]) <- paste(colnames(listofdfs[i]), i)
}

This error occurs

Error in `*tmp*`[i] : invalid subscript type 'list'

Attempt 2

for (i in listofdfs){
        newnames <- paste(colnames(listofdfs[i]), i)
        colnames(bsl) <- newnames
}

This error occurs

No error is printed, however when I check one of the dataframes' columns the column names remain unchanged.

Attempt 3

for (i in listofdfs){
        colnames(listofdfs[[i]]) <- paste(colnames(listofdfs[[i]]), i)
}

This error occurs

Error in listofdfs[[i]] : invalid subscript type 'list'

回答1:

Below is a code that renames the column names of each data.frame in a list in a way so that names of data.frames are added to original column names.

# example data
a <- data.frame(col1 = 1:10, col2 = 10:1)
b <- data.frame(col_01 = 11:20, col_02 = 20:11)

# list of data.frames
list_of_df <- list(a, b)

# names of data.frames
names(list_of_df) <- c("a", "b")

# my sequence and names of data.frames in a list
my_seq <- seq_along(list_of_df)
my_list_names <- names(list_of_df)

# procedure
for (i in my_seq) {

  names(list_of_df[[my_seq[i]]]) <- 
    paste(my_list_names[i], names(list_of_df[[my_seq[i]]]), sep = "_")

}

list_of_df

$a
   a_col1 a_col2
1       1     10
2       2      9
3       3      8
4       4      7
5       5      6
6       6      5
7       7      4
8       8      3
9       9      2
10     10      1

$b
   b_col_01 b_col_02
1        11       20
2        12       19
3        13       18
4        14       17
5        15       16
6        16       15
7        17       14
8        18       13
9        19       12
10       20       11

回答2:

you are almost there. do something like this

for (i in seq_along(listofdfs)){
    colnames(listofdfs[[i]]) <- paste(colnames(listofdfs[[i]]), i)
}

this should execute your logic of creating column names without any error.

Why

for (i in listofdfs){
        colnames(listofdfs[[i]]) <- paste(colnames(listofdfs[[i]]), i)
}

Because you are expecting i to be a index but rather it is a data.frame itself. Debug using print

for (i in listofdfs){
    print(class(i))
}

this is what you get

[1] "data.frame"
[1] "data.frame"

you cant subscript using a data.frame. forloop with in operator in R iterates along the individual elements and not their indexes. Hence we have to use seq_along

Hope this helps.