我有复数的数据集,我希望能够找到最适合的数据参数。 你能适应在使用leastsq复数数据由SciPy的Python中实现?
例如,我的代码是这样的:
import cmath
from scipy.optimize import leastsq
def residuals(p,y,x):
L,Rs,R1,C=p
denominator=1+(x**2)*(C**2)*(R1**2)
sim=complex(Rs+R1/denominator,x*L-(R1**2)*x*C/denominator)
return(y-sim)
z=<read in data, store as complex number>
x0=np.array[1, 2, 3, 4]
res = leastsq(residuals,x0, args=(z,x))
然而, residuals
不喜欢和我的复数的工作,我得到的错误:
File "/tmp/tmp8_rHYR/___code___.py", line 63, in residuals
sim=complex(Rs+R1/denominator,x*L-(R1**_sage_const_2 )*x*C/denominator)
File "expression.pyx", line 1071, in sage.symbolic.expression.Expression.__complex__ (sage/symbolic/expression.cpp:7112)
TypeError: unable to simplify to complex approximation
我猜,我只需要与工作花车/双打,而不是复数。 在这种情况下,我怎么能单独评估真实和复杂的零件,然后就把他们都回来一起到一个单一的错误度量residuals
返回?