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问题:
I want to allow users to enter password using command-line interface. but I don't want to display this password on screen (or display "****").
How to do it in C?
Thanks.
Update:
I'm working on Linux only. So I don't actually care about Win or other systems. I tried Lucas' solution and it worked fine. However, I still have another question:
If this is a single process & single thread app, changing setting of termios affects different terminals?
How about 1 process - multi threads, multi processes - multi threads?
Thanks very much.
回答1:
If your system provides it, getpass is an option:
#include <unistd.h>
/* ... */
char *password = getpass("Password: ");
This will not display anything as characters are typed.
回答2:
If you are using a UNIX environment something like this can turn off the ECHO of the command-line.
#include <stdio.h>
#include <termios.h>
#include <unistd.h>
#define SIZE 100
void getPassword(char password[])
{
static struct termios oldt, newt;
int i = 0;
int c;
/*saving the old settings of STDIN_FILENO and copy settings for resetting*/
tcgetattr( STDIN_FILENO, &oldt);
newt = oldt;
/*setting the approriate bit in the termios struct*/
newt.c_lflag &= ~(ECHO);
/*setting the new bits*/
tcsetattr( STDIN_FILENO, TCSANOW, &newt);
/*reading the password from the console*/
while ((c = getchar())!= '\n' && c != EOF && i < SIZE){
password[i++] = c;
}
password[i] = '\0';
/*resetting our old STDIN_FILENO*/
tcsetattr( STDIN_FILENO, TCSANOW, &oldt);
}
int main(void)
{
char password[SIZE];
printf("please enter password\n");
getPassword(password);
printf("Do something with the password <<%s>>\n", password);
return 0;
}
回答3:
The function getpass is now obsolete. Use termios.
#include <termios.h>
#include <stdio.h>
void get_password(char *password)
{
static struct termios old_terminal;
static struct termios new_terminal;
//get settings of the actual terminal
tcgetattr(STDIN_FILENO, &old_terminal);
// do not echo the characters
new_terminal = old_terminal;
new_terminal.c_lflag &= ~(ECHO);
// set this as the new terminal options
tcsetattr(STDIN_FILENO, TCSANOW, &new_terminal);
// get the password
// the user can add chars and delete if he puts it wrong
// the input process is done when he hits the enter
// the \n is stored, we replace it with \0
if (fgets(password, BUFSIZ, stdin) == NULL)
password[0] = '\0';
else
password[strlen(password)-1] = '\0';
// go back to the old settings
tcsetattr(STDIN_FILENO, TCSANOW, &old_terminal);
}
int main(void)
{
char password[BUFSIZ];
puts("Insert password:");
get_password(password);
puts(password);
}
回答4:
For C/commandline/linux see:
man getch
man noecho
see the coment in getch
about noecho
. I've never tried this myself.
In bash if you use read -s
it does not echo on the screen:
> read -s x
<type something><enter>
> echo $x
<whatever you typed>
回答5:
To do this in a portable way you will need to use a standardized or de-facto standard library.
See man 3 termios
and man 3 ncurses
.
Here is a program that will work on Linux and other Unix systems...
#include <stdio.h>
int main(void) {
int f = open("/dev/tty", 0);
char s[100];
system("stty -echo > /dev/tty");
f >= 0 && read(f, s, sizeof s) > 0 && printf("password was %s", s);
system("stty echo > /dev/tty");
return 0;
}
A number of improvements are possible. Using termios would probably be better, and it would avoid the fork and possible security issues of system(). Using standard I/O to read the password would probably be better. (As written the typed newline would have to be deleted.) There is a getpass() function in Linux and some others however it is marked as "obsolete. Do not use it.". It might be a good idea to deal with SIGTSTP.
Overall, I might look for an existing solution that deals with all these little issues...
回答6:
If you have access to the curses library, you can use noecho. If you're using Microsoft's C compiler, you can use _getch. But afaik, both of these tie you to the console. If you need to read stdin regardless of whether it comes from the console or a file or a piped command, you need to tell the operating system how it should handle the console.
回答7:
#include<conio.h>
#include<iostream>
using namespace std;
int main(){
char *pass = new char[20];
cout<<"Password :";
int i=0;
while( ( pass[i]=getch() ) != '\n' && pass[i] != '\r' && i<19 )
{putchar('*'); i++;}
pass[i]='\0';
cout<<endl;
if(strcmp("123456789",pass)==0 ) // do stuff
return 0;}