Basically I need to write a program that takes user input up to and including 2^31 -1 in the form of an integer and returns the amount of odd, even, and zero numbers in the int. For example,
Input: 100
Output: 1 Odd, 0 Even, 2 Zeros // 1(Odd)0(Zero)0(Zero)
or
Input: 2034
Output: 1 Odd, 2 Even, 1 Zero // 2(Even)0(Zero)3(Odd)4(Even)
I'm pretty sure I'm over thinking it but I can't slow my brain down. Can anyone help?
This is the third iteration of the code, the first two were attempted with for loops.
import java.util.Scanner;
public class oddEvenZero
{
public static void main(String[] args) {
Scanner scan = new Scanner (System.in);
int value;
int evenCount = 0, oddCount = 0, zeroCount = 0;
System.out.print("Enter an integer: ");
value = scan.nextInt();
while (value > 0) {
value = value % 10;
if (value==0)
{
zeroCount++;
}
else if (value%2==0)
{
evenCount++;
}
else
{
oddCount++;
}
value = value / 10;
}
System.out.println();
System.out.printf("Even: %d Odd: %d Zero: %d", evenCount, oddCount, zeroCount);
}
}
Sorry, the code formatted weirdly in the textbox.
value = value % 10;
Probably the end-all-be-all of your problems.
If value is 2034, then value % 10 returns 4... and then assigns that value to value, you go through your if else block, then do 4/10 get 0, and exit the while loop without addressing the other 3 digits.
I suggest something more like this:
while (value > 0) {
if ((value%10)==0) {
zeroCount++;
}
else if (value%2==0) { //As per comment below...
evenCount++;
}
else {
oddCount++;
}
value /= 10;
}
Or, int thisDigit = value % 10, then replace value in your current if else block with thisDigit.
value = value % 10;
This statement will override your original value with a reminder i.e value % 10.
If value = 2034 and value % 10 = 4, then value = 4 which isn't what you want.
Instead use a temporary variable
int lastDigit = value % 10;
Then your code becomes;
while (value > 0) {
int lastDigit = value % 10;
if (lastDigit==0)
{
zeroCount++;
}
else if (lastDigit%2==0)
{
evenCount++;
}
else
{
oddCount++;
}
value = value / 10;
}
import java.util.Scanner;
public class oddEvenZero
{
public int[] convertStringArraytoIntArray(String[] sarray) throws Exception {
if (sarray != null)
{
int k= sarray.length-1;
int intarray[] = new int[k];
for (int i = 1; i < sarray.length; i++) {
intarray[i-1] = Integer.parseInt(sarray[i]);
}
return intarray;
}
return null;
}
public static void main(String[] args) {
Scanner scan = new Scanner (System.in);
String value;
System.out.print("Enter an integer: ");
value = scan.next();
String words[] = value.split("");
oddEvenZero obj = new oddEvenZero();
try{
int intarray[]= obj.convertStringArraytoIntArray(words);
int even_number =0;
int odd_number =0;
int zero_number =0;
for (int h: intarray)
{
if(h==0)
{
zero_number++;
}
else if(h%2==0)
{
even_number++;
}
else{
odd_number++;
}
}
System.out.println("even numbers are"+ even_number);
System.out.println("odd numbers are"+odd_number);
System.out.println("Zero numbers are"+zero_number);
}
catch(Exception ex)
{
System.out.println("Please enter number");
}
}
}
If some of you are still unable to figure this code out, I found this while searching around for a bit, and works just fine:
import java.util.*;
public class Java_1
{
public static void main (String[] args)
{
String string;
int zero = 0, odd = 0, even = 0, length, left = 0;
Scanner scan = new Scanner(System.in);
System.out.print ("Enter any positive number: ");
string = scan.next();
length = string.length();
while (left < length)
{
string.charAt(left);
if (string.charAt(left) == 0)
zero++;
else if (string.charAt(left) % 2 == 0)
even++;
else
odd++;
left++;
}
System.out.println ("There are: "+ zero + " zeros.");
System.out.println ("There are: "+ even + " even numbers.");
System.out.println ("There are: "+ odd + " odd numbers.");
}
}
