I wanted to set the position of a div based on the return value of a function in an angular controller
The following works fine in FireFox and in chrome but in Internet explorer {{position($index)}}%
is interpreted as a literal string value and therefore has no effect
<div ng-repeat="item in items" style="left:{{position($index)}}%"></div>
Here is an example of the issue:
var app = angular.module('app', []);
app.controller('controller', function($scope) {
$scope.items=[1,2,3,4,5,6,7,8,9,10];
$scope.position=function(i){
var percent =[5,10,15,20,25,30,35,40,45,50,55,60,65,70];
return percent[i+1];
}
});
And here is a Fiddle to demonstrate
Does anyone have suggestions on how to rectify?
You must use ng-style instead of style, otherwise some browsers like IE
will remove invalid style attribute values (presence of {{}}
etc makes it invalid) before even angular has a chance to render it. When you use ng-style
angular will calculate the expression and add the inline style attributes to it.
<div ng-repeat="item in items" ng-style="{left: position($index) + '%'}"></div>
Since you are anyways calculating the position you could as well add %
from the position
and send it. Also remember that calling a function in ng-repeat will invoke the function every digest cycle, so you may want to be careful not to do too much intensive operations inside the method.
<div ng-repeat="item in items" ng-style="{left: position($index)}">{{item}}</div>
and return
return percent[i+1] + "%";
Demo
If you want to use angular binding expression {{}}
just like normal style attribute like style="width:{{someScopeVar}}"
,
use ng-attr-style
and it will work perfectly IE (and obviously other smarter ones) :)
check my jsFiddle ... Checked with Angular JS 1.4.8
here I have shown the usage of style
, ng-style
and ng-attr-style
THE HTML
<div ng-app="app">
<div ng-controller="controller">
<div style="background:{{bgColor}}">
This will NOT get colored in IE
</div>
<div ng-attr-style="background:{{bgColor}}">
But this WILL get colored in IE
</div>
<div ng-style="styleObject">
And so is this... as this uses a json object and gives that to ng-style
</div>
</div>
</div>
THE JS
var app = angular.module('app', []);
app.controller('controller', function($scope) {
$scope.bgColor = "yellow";
$scope.styleObject = {"background": "yellow"};
});
Yes, ng-style
will work to resolve this problem. You can use conditionally style using ternary operator
.
HTML:
<div ng-style="{'display':showInfo?'block':'none'}">
</div>