Escape single quote in xslt concat function

2019-01-14 20:18发布

问题:

I want to output single quote around $ID variable in the below xsl:value-of xsl statment.

<xsl:value-of select="concat('process[@Ref=',$ID,']')"></xsl:value-of>

currently it prints

process@Ref=87799989

Please let me know how can i achieve this.

Thanks in advance, Keshav

回答1:

Use &apos;?

<xsl:value-of select="concat('process[@Ref=&apos;',$ID,'&apos;]')"></xsl:value-of>

Edit: See Dimitre's answer for a better solution.



回答2:

In XPath 1.0:

You can use the built-in entities &apos; and &quot;

In XSLT 1.0:

Alternatively, you can define your $Q and $APOS variables (put the content (the literal " or the literal ' character) in the body of the xsl:variable, not in the select attribute).

In XPath 2.x (this also means XSLT 2.x and XQuery 1.x)

Simply escape an apostrophe by entering two adjacent apostrophes, escape a quote by entering two adjacent quotes, as defined by the XPath 2.0 language



回答3:

To expand on Dimitre's answer, you can use this solution in XSLT:

<xsl:variable name="apos">'</xsl:variable>
<xsl:value-of select="concat('process[@Ref=',$apos,$ID,$apos,']')"></xsl:value-of>


回答4:

<xsl:value-of
select="concat('process[@Ref=&apos;',$ID,'&apos;]')"></xsl:value-of>

this doesn't work for me. My solution is:

<xsl:value-of select="concat(&quot;process[@Ref='&quot;,$oidConstant,&quot;'&quot;)"></xsl:value-of>


回答5:

Easy Example would be

      <xsl:variable name="varTitle" select="title" />
<xsl:variable name="APOS">'</xsl:variable>
<xsl:value-of select="translate($varTitle, 'any text', $APOS)"/>

This will replace "any text" with ' in my title.