my convert code is all i have, but it converts a string to sha-1 to hex format. how can i convert sha-1 to base64 ?
-(NSString *)digest:(NSString*)input
int i;
const char *cstr = [input cStringUsingEncoding:NSUTF8StringEncoding];
NSData *data = [NSData dataWithBytes:cstr length:input.length];
uint8_t digest[CC_SHA1_DIGEST_LENGTH];
CC_SHA1(data.bytes, data.length, digest);
output = [NSMutableString stringWithCapacity:CC_SHA1_DIGEST_LENGTH * 2];
length:CC_SHA1_DIGEST_LENGTH];
for(i = 0; i < CC_SHA1_DIGEST_LENGTH; i++)
{
[output appendFormat:@"%02x", digest[i]];
}
return output;
}
There's no built-in hashing or Base64 in iOS. You'll have to roll your own. Find a C implementation of SHA1 in Google; as for Base64, I've got one for you:
NSString *ToBase64(NSData *d)
{
static const char ALPHABET[] = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";
static const NSString *PAD1 = @"=", *PAD2 = @"==";
int l = [d length];
unsigned char *p = (unsigned char*)[d bytes];
unichar Chunk[4];
NSMutableString *s = [NSMutableString stringWithCapacity:(l+3)*4/3];
int i;
int mod = l % 3;
int ll = l - mod;
unsigned int triad;
NSString *sChunk;
for(i=0;i<ll;i+=3)
{
triad = (p[i]<<16) | (p[i+1]<<8) | p[i+2];
Chunk[0] = ALPHABET[(triad >> 18) & 0x3f];
Chunk[1] = ALPHABET[(triad >> 12) & 0x3f];
Chunk[2] = ALPHABET[(triad >> 6) & 0x3f];
Chunk[3] = ALPHABET[triad & 0x3f];
sChunk = [[NSString alloc] initWithCharacters:Chunk length:4];
[s appendString:sChunk];
[sChunk release];
}
if(mod == 1)
{
Chunk[0] = ALPHABET[(p[i] >> 2) & 0x3f];
Chunk[1] = ALPHABET[(p[i] << 4) & 0x3f];
sChunk = [[NSString alloc] initWithCharacters:Chunk length:2];
[s appendString:sChunk];
[sChunk release];
[s appendString: PAD2];
}
if(mod == 2)
{
triad = (p[i]<<8) | p[i+1];
Chunk[0] = ALPHABET[(triad >> 10) & 0x3f];
Chunk[1] = ALPHABET[(triad >> 4) & 0x3f];
Chunk[2] = ALPHABET[(triad << 2) & 0x3f];
sChunk = [[NSString alloc] initWithCharacters:Chunk length:3];
[s appendString:sChunk];
[sChunk release];
[s appendString: PAD1];
}
return s;
}