SQL RANK（）在PARTITION上连接的表(SQL RANK() over PARTITIO

我有两个表RSLTS和联系方式：

RSLTS

 QRY_ID  |  RES_ID  |  SCORE
-----------------------------
   A     |    1     |    15
   A     |    2     |    32
   A     |    3     |    29
   C     |    7     |    61
   C     |    9     |    30

联系

 C_ID  |  QRY_ID  |  RES_ID
----------------------------
  1    |    A     |    2
  2    |    A     |    1
  3    |    C     |    9

我试图创建一份报告，显示每个联系人记录（ C_ID ）时， RANK()的RES_ID （由SCORE其组内（在RSLTS表） QRY_ID ）。 使用上面的数据，它是这样的：

 C_ID  |  QRY_ID  |  RES_ID  |  SCORE  |  Rank
-----------------------------------------------
  1    |    A     |    2     |    32   |   1
  2    |    A     |    1     |    15   |   3
  3    |    C     |    9     |    30   |   2

到目前为止，我试过，但它返回等级= 1的最后一行（和秩= 2的第二个，这也是错误的）

SELECT
    C.*
    ,R.SCORE
    ,RANK() OVER (PARTITION BY R.QRY_ID ORDER BY R.SCORE DESC)
FROM CONTACTS C LEFT JOIN RSLTS R
ON C.RES_ID = R.RES_ID
AND C.QRY_ID = R.QRY_ID

更新： SQLFiddle

Answer 1:

由于排名不从接触取决于在所有

RANKED_RSLTS

 QRY_ID  |  RES_ID  |  SCORE |  RANK
-------------------------------------
   A     |    1     |    15  |   3
   A     |    2     |    32  |   1
   A     |    3     |    29  |   2
   C     |    7     |    61  |   1
   C     |    9     |    30  |   2

因此：

SELECT
    C.*
    ,R.SCORE
    ,MYRANK
FROM CONTACTS C LEFT JOIN
(SELECT  *,
 MYRANK = RANK() OVER (PARTITION BY QRY_ID ORDER BY SCORE DESC)
  FROM RSLTS)  R
ON C.RES_ID = R.RES_ID
AND C.QRY_ID = R.QRY_ID

Answer 2:

SELECT a.C_ID,a.QRY_ID,a.RES_ID,b.SCORE,ROW_NUMBER() OVER (ORDER BY SCORE DESC) AS [RANK]
FROM CONTACTS a JOIN RSLTS b ON a.QRY_ID=b.QRY_ID AND a.RES_ID=b.RES_ID
ORDER BY a.C_ID

文章来源: SQL RANK() over PARTITION on joined tables