red parsing and replacing double % with <> does

问题:

I want to transform

 test: "bla bla %bla bla% bla bla bla bla %bla% bla"

into

 test: "bla bla <bla bla> bla bla bla bla <bla> bla"

with this code, it doesn't work in red:

 rules: [
    (toggle: -1)
    to "%" mark: (
        (toggle: 0 - toggle)
        either (toggle = 1) [change mark {<}][change mark {>}]
    )
    thru "%"
    |
    to end
]

parse test rules

Output is

>> test
== "bla bla <bla bla% bla bla bla bla %bla% bla"

回答1:

Your rules need a little more care, especially when using the keywords 'to and 'thru. The way your rule is written the replacement will occur once and then to end will advance you to the end of the input -- not what you want.

I'll step through it slowly.

The first rule, the to "%", this advances the input to the first "%" character. It's a successful rule so your parens expression executes and modifies the input, i.e., changes the "%" to a "<". All good there: the first replacement is complete and the very next char in the input is now "<". BUT your next rule is thru "%". This advances the input past the next "%" character in the input-- a char you want changed to ">".

The other key piece here (as HostileFork points out) is that your replacement rule is not repeating. Your parse rule runs once and then it's over. Your alternative rule to end then takes over and jumps the input all way to the end. In order to get a rule to scan repeatedly through the entire input you need to set up your rule with a some, any, while or skip.

Here's a quick rework of your rule leaving most of your code in place but achieving the result I think you want.

test: "bla bla %bla bla% bla bla bla bla %bla% bla"
toggle: -1
rules: [any [
    to "%" mark: (
        toggle: negate toggle 
        either toggle = 1 [change mark "<"][change mark ">"]
    ) 
    ]
]
parse test rules
test
 == "bla bla <bla bla> bla bla bla bla <bla> bla"

There are other things in the code that I would probably change, such as the toggle, and you can see I got rid of unecessary parentheses, but for now I'm forcusing on the way parse works.

回答2:

You don't have any iterative construct in your parse rule (SOME, ANY, WHILE, etc.) So it shouldn't be surprising it does one replacement and stops.

This will give you the desired output, and has a couple other changes for consideration (though just including the any [... | skip] modification would have fixed your code):

rules: [
    (toggle: true)
    any [
        to "%" mark: thru "%" (
            change mark pick [{>} {<}] (toggle: not toggle)
        )
    |
        skip
    ]
]

parse test rules

(I'm not the biggest fan of using PICK with a LOGIC!...it gives you the first element if true and the second if false, but throwing it in here for fun.)

回答3:

Two solutions: one without parse

test: "bla bla %bla bla% bla bla bla bla %bla% bla"
replace test "%" "<"
replace test "%" ">"
replace test "%" "<"
replace test "%" ">"

and one with parse

test: "bla bla %bla bla% bla bla bla bla %bla% bla"
parse test [some [to "%" change skip "<"  to "%" change skip ">"] to end]

and one for fun

parse test [(tog: next [">" "<"]) some [to "%" change skip tog  (reverse head tog)] to end]