如何创建代理类?(How to create proxy class?)

2019-08-03 18:40发布

N有没有公开的数据字段difrent类,只有方法(不重叠),如何创建通过升压预处理器unifiing所有这些代理类?

例如,我们过班:一个是有方法do(); 和B类有方法data(); 。 我不知道是否有(使用Boost预处理器为例)的方式(在这里创建一个代理类,将有来自A和B的所有方法do() data()和一个构造函数在这方面采取指针,指向类的实例-一个对于A和一个对于B?

所以,我们会得到API像这样的伪代码:

JOIN(A, B, C);// or if needed JOIN("path_to_A.h", "path_to_B.h", C)
//...
A * a = new A();
B * b = new B();
C * c = new C(a, b);
c->data();
c->do();

是否有可能在C ++ 11创造这样的事情使用boost :: preprovcessor或可能有这样的事情已经在推动?

此外,如果这样的事情是可能使用外部生成它会没事的我。

Answer 1:

如果你不介意上市A和B的所有方法,我们可以用SFINAE做到这一点。 这里的essense是,我们定义了两个方法C::data()其前进到每个A::data()B::data() 编译器将过滤掉不能被编译的一个,因此,我们可以把它转发给正确的成员。

#include <type_traits>
#include <boost/preprocessor/seq/for_each.hpp>

#define CALLER_NAME(method_name) BOOST_PP_CAT(BOOST_PP_CAT(_, method_name), _caller__)

#define GEN_CALLER(r, ignored, method_name) \
    template <typename K, typename... T> \
    static auto CALLER_NAME(method_name)(K* k, T&&... args) -> decltype(k->method_name(std::forward<T>(args)...)) { \
        return k->method_name(std::forward<T>(args)...); \
    } \
    template <typename... T> \
    auto method_name(T&&... args) -> decltype(CALLER_NAME(method_name)(_first__, std::forward<T>(args)...)) { \
        return CALLER_NAME(method_name)(_first__, std::forward<T>(args)...); \
    } \
    template <typename... T> \
    auto method_name(T&&... args) -> decltype(CALLER_NAME(method_name)(_second__, std::forward<T>(args)...)) { \
        return CALLER_NAME(method_name)(_second__, std::forward<T>(args)...); \
    }

#define JOIN(FIRST, SECOND, NAME, METHODS) \
    struct C { \
        FIRST* _first__; \
        SECOND* _second__; \
        NAME(FIRST* _first__, SECOND* _second__) : _first__(_first__), _second__(_second__) {} \
        BOOST_PP_SEQ_FOR_EACH(GEN_CALLER, , METHODS) \
    }

例如:

struct A {
    int x;

    void a() {
        std::cout << "an a! " << x << "\n";
    }
};

struct B {
    double x;

    double b(double k) {
        std::cout << "b! " << x << ", " << k << "\n";
        return x - k;
    }

    void b() {
        std::cout << "b! " << x << ", ?\n";
    }
};

JOIN(A, B, C, (a)(b));

int main() {
    A a {12};
    B b {24};

    C c (&a, &b);

    c.a();
    c.b();
    std::cout << c.b(2445) << std::endl;
}

这个想法可以推广到超过2类:

#include <type_traits>
#include <boost/preprocessor/seq/for_each.hpp>
#include <boost/preprocessor/seq/for_each_i.hpp>
#include <boost/preprocessor/punctuation/comma_if.hpp>

#define CALLER_NAME(method_name) \
    BOOST_PP_CAT(BOOST_PP_CAT(_caller_, method_name), __)
#define FIELD_NAME(ClassName) \
    BOOST_PP_CAT(BOOST_PP_CAT(_field_, ClassName), __)
#define INVOKER_IMPL(method_name, ClassName) \
    CALLER_NAME(method_name)(FIELD_NAME(ClassName), std::forward<T>(args)...)
#define CALLER_IMPL(method_name) \
    k->method_name(std::forward<T>(args)...)
#define FORWARD(IMPL) -> decltype(IMPL) { return IMPL; }

#define GEN_INVOKER(r, method_name, i, ClassName) \
    template <typename... T> \
    auto method_name(T&&... args) \
        FORWARD(INVOKER_IMPL(method_name, ClassName))

#define GEN_CALLER(r, ALL_CLASSES, method_name) \
private: \
    template <typename K, typename... T> \
    static auto CALLER_NAME(method_name)(K* k, T&&... args) \
        FORWARD(CALLER_IMPL(method_name)) \
public: \
    BOOST_PP_SEQ_FOR_EACH_I_R(r, GEN_INVOKER, method_name, ALL_CLASSES)

#define GEN_FIELD(r, IGNORED, ClassName) \
    ClassName* FIELD_NAME(ClassName);
#define GEN_ARG(r, IGNORED, i, ClassName) \
    BOOST_PP_COMMA_IF(i) ClassName* FIELD_NAME(ClassName)
#define GEN_CTOR(r, IGNORED, i, ClassName) \
    BOOST_PP_COMMA_IF(i) FIELD_NAME(ClassName)(FIELD_NAME(ClassName))

#define JOIN(ALL_CLASSES, ClassName, METHODS) \
    struct ClassName { \
    private: \
        BOOST_PP_SEQ_FOR_EACH(GEN_FIELD, , ALL_CLASSES) \
    public: \
        ClassName(BOOST_PP_SEQ_FOR_EACH_I(GEN_ARG, , ALL_CLASSES)) \
            : BOOST_PP_SEQ_FOR_EACH_I(GEN_CTOR, , ALL_CLASSES) {} \
        BOOST_PP_SEQ_FOR_EACH(GEN_CALLER, ALL_CLASSES, METHODS) \
    }

用法:

struct A {
    int x;

    void a() {
        std::cout << "an a! " << x << "\n";
    }
};

struct B {
    double x;

    double b(double k) {
        std::cout << "b! " << x << ", " << k << "\n";
        return x - k;
    }

    void c() {
        std::cout << "b! " << x << ", ?\n";
    }
};

struct C {
    double x;

    double c(double k) {
        std::cout << "c! " << x << ", " << k << "\n";
        return x + k;
    }

    void b() {
        std::cout << "c! " << x << ", ?\n";
    }
};


JOIN((A)(B)(C), D, (a)(b)(c));

int main() {
    A a {12};
    B b {24};
    C c {36};

    D d {&a, &b, &c};

    d.a();
    d.b();
    d.c();
    std::cout << d.b(48) << std::endl;
    std::cout << d.c(64) << std::endl;
}


文章来源: How to create proxy class?