Remove the empty elements while using copy-of usin

问题:

Ed: following from Copy parallel element as child element of another element:

Input XML

<root>
   <order orderId="12345">
      <cartId>12346</cartId>
       <orderPayment paymentId="1234">
      <debitCardPayment>
         <chargeAmount currencyCode="USD">22.20</chargeAmount>
         <debitCard>
            <PIN>1234</PIN>  
            <PIN1></PIN1>               
         </debitCard>
      </debitCardPayment>
   </orderPayment>
   </order>
   <context>
   </context>       
</root>

Need OUTPUT

<order>
  .....
</order>
 <orderPayment>
   .....
       <debitCard>
            <PIN>1234</PIN>  
         </debitCard>
</orderPayment>
<context>
</context>

I have XSLT as follows

<xsl:template match="Root">
        <updateOrderCheckoutRequest version="1"> 
            <xsl:apply-templates select="@*|node()"/>
            <xsl:copy-of select="//orderPayment"/>
        </updateOrderCheckoutRequest>
    </xsl:template>      

      <xsl:template match="orderPayment"/>

      <xsl:template match="order"> 
         <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy> 
      </xsl:template>

    <xsl:template match="@*|node()">
        <xsl:choose>
            <xsl:when test=".='' and count(@*)=0">
                <xsl:apply-templates select="@*|node()"/>
            </xsl:when>
            <xsl:otherwise>
                <xsl:copy>
                    <xsl:apply-templates select="@*|node()"/>
                </xsl:copy>
            </xsl:otherwise>
        </xsl:choose>
    </xsl:template>

Which is copying empty elements also. Is there any possibility to remove empty elements while applying copy-of. Thanks in advance...

回答1:

Is there any possibility to remove empty elements while applying copy-of.

No, it is not possible to use xsl:copy-of without copying everything as is. If you want to apply further changes to the nodes being copied, you must employ a different strategy, for example:

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<!-- identity transform -->
<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="/root">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()[not(self::orderPayment)]"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="order">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
        <xsl:apply-templates select="../orderPayment"/>
    </xsl:copy>
</xsl:template>

</xsl:stylesheet>

Now the orderPayment is being "copied" by virtue of the identity transform template - and you can add more specific templates to override, such as:

<xsl:template match="PIN1[not(string())]"/>

to remove empty PIN1 elements.

回答2:

Please try the following stylesheet:

<xsl:stylesheet version="1.0" 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

    <xsl:strip-space elements="*"/>
    <xsl:output indent="yes"/>

    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>

    <xsl:template match="/root">
        <updateOrderCheckoutRequest version="1"> 
            <xsl:apply-templates select="@*|node()"/>
        </updateOrderCheckoutRequest>
    </xsl:template>

    <xsl:template match="order">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()[not(self::orderPayment)]"/>
        </xsl:copy>
        <xsl:apply-templates select="orderPayment"/>
    </xsl:template>

    <xsl:template match="*[not(string())]"/>

</xsl:stylesheet>