我使用谷歌浏览器。
使用Twitter的引导 ，我想补充一个简单的警报，不幸的是， 警报时，按下X不解散！
下面是根据我的代码警报文档：
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js" type="text/javascript"></script>
<!-- Bootstrap -->
<link href="css/bootstrap.min.css" rel="stylesheet" media="screen">
</head>
<body>
<div class="alert">
<button type="button" class="close" data-dismiss="alert">×</button>
<strong>Warning!</strong> Best check yo self, you're not looking too good.
</div>
</body>
</html>
我也尝试：
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js" type="text/javascript"></script>
<!-- Bootstrap -->
<link href="css/bootstrap.min.css" rel="stylesheet" media="screen">
</head>
<body>
<div class="alert">
<a href="#" class="close" data-dismiss="alert">×</a>
<strong>Warning!</strong> Best check yo self, you're not looking too good.
</div>
</body>
</html>
缺什么，使它解雇？
