JAXB Mapping to JSON

问题:

I have written a JAX-RS (Jersey) REST Service, which accepts XML messages of ONIX XML format. Generally, I have generated all the required classes for JAXB binding from the given schema with xjc. There are more than 500 classes overall and I cannot modify them.

Now, when I have a JAXB-mapped object, I need to store it to the database. I work with mongoDb, so the message format should be JSON. I tried to use Jackson with JAXB module to convert JAXB-object into JSON, which works pretty fine with storing the data. But when I try to convert the JSON back into the JAXB object, it throws an exception connected somehow with the JAXBElement. In google I found out that the JAXBElement is not supported in Jackson and I have to work around this issue. But I cant do it because I cannot modify JAXB-generated classes.

Is there a way to map JAXB Objects into JSON with some other means, but which will follow the whole JAXB specification so that I have no problems in the future converting from JSON to the JAXB object and visa vera?

回答1:

Note: I'm the EclipseLink JAXB (MOXy) lead and a member of the JAXB (JSR-222) expert group.

If you can't do it with Jackson, you use case will work with MOXy.

Java Model

Foo

Here is a sample class that contains a field of type JAXBElement.

import javax.xml.bind.JAXBElement;
import javax.xml.bind.annotation.*;

@XmlAccessorType(XmlAccessType.FIELD)
public class Foo {

    @XmlElementRef(name="bar")
    private JAXBElement<Bar> bar;

}

Bar

public class Bar {

}

ObjectFactory

import javax.xml.bind.JAXBElement;
import javax.xml.bind.annotation.*;
import javax.xml.namespace.QName;

@XmlRegistry
public class ObjectFactory {

    @XmlElementDecl(name = "bar")
    public JAXBElement<Bar> createBar(Bar bar) {
        return new JAXBElement<Bar>(new QName("bar"), Bar.class, bar);
    }

}

Standalone Demo Code

Below is some demo code you can run in Java SE to see that everything works:

Demo

import java.util.*;
import javax.xml.bind.*;
import javax.xml.transform.stream.StreamSource;

import org.eclipse.persistence.jaxb.JAXBContextProperties;

public class Demo {

    public static void main(String[] args) throws Exception {
        Map<String, Object> properties = new HashMap<String, Object>(2);
        properties.put(JAXBContextProperties.MEDIA_TYPE, "application/json");
        properties.put(JAXBContextProperties.JSON_INCLUDE_ROOT, false);
        JAXBContext jc = JAXBContext.newInstance(new Class[] {Foo.class, ObjectFactory.class}, properties);

        Unmarshaller unmarshaller = jc.createUnmarshaller();
        StreamSource json = new StreamSource("src/forum19158056/input.json");
        Foo foo = unmarshaller.unmarshal(json, Foo.class).getValue();

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(foo, System.out);
    }

}

input.json/Output

{"bar" : {} }

Running with JAX-RS

The following links will help you leverage MOXy in a JAX-RS service:

• http://blog.bdoughan.com/2012/05/moxy-as-your-jax-rs-json-provider.html
• http://blog.bdoughan.com/2013/06/moxy-is-new-default-json-binding.html

回答2:

Since you're using Jackson you can construct an ObjectMapper with the JaxbAnnotationModule and write out the value. The following is some code to write a JAXB annotated object to system out.

ObjectMapper mapper = new ObjectMapper();
mapper.registerModule(new JaxbAnnotationModule());
        mapper.writeValue(System.out, jaxbObject);

This approach will also work on Glassfish as it does not utilize the provider given by the container which would cause ClassNotFoundException as per GLASSFISH-21141