我是相当新的编程，这是我在创建使用Python复杂的脚本首次尝试
我创建该计划的目的是：
- 要经过文件的列表（360个文件一起在一个文件夹中）
- 在文件名中提取3个独特的字符和创建基于3个字符的文件夹（60个唯一文件夹共）
- 创建一个for循环，其经过在源文件夹中的文件列表并将其移动到其对应的目标文件夹。
例：
文件名：KPHI_SDUS81_N3KDIX_201205261956
文件夹中创建基于字符：N3K
import os
#Creates a list based on file names in the folder
srcfile=os.listdir("E:\\Learning Python\\Testing out\\thunderstorm stuff")
#Directiory of where the source files are located
srcpath= "E:\\Learning Python\\Testing out\\thunderstorm stuff"
#Creates a list based on the location of where folders will be lcoated.
#List will be empty since for loop has not ran yet
targetsrc=os.listdir("E:\\Learning Python\\Testing out\\test folder")
#path of where the new folders created will be located
targetpath = "E:\\Learning Python\\Testing out\\test folder"
#empty list created to hold a string of 3 characters (see for loop below)
list=[]
#A list to hold the unique string values. (see 2nd for loop below)
Target=[]
#the for loop below looks at a file and gooes to the character place holder index of 12 and looks at the characters UP TO 15.
#It then assigns the three characters to a variable x which then passes the the string (the 3 characters) to an empty list called list.
for num in srcfile:
x=num[12:15]
list.append(x)
#a test to see if the for loop above was able to exact the three characters from the list
print list
print srcfile
#created to see how big the list is which should match the amount of files in folder
print len(srcfile)
print len (list)
#a function created to make a folder based on a list
def create(s):
targetpath = "E:\\Learning Python\\Testing out\\test folder"
test=os.mkdir(os.path.join(targetpath,s))
#a dummy variable holder for the for loop below
valhold = "null"
#a nested if statement inside a for loop.
#The for loop goes through all the string values in a list called "list" (assigned to folder in for loop)
#and checks it against a list called valhold. If folder and valhold are not equal,
#the values in folder are appened to a list called Target.append which holds unique values.
#The next step is to create a folder a folder based off the list value "valhold"
for folder in list:
if folder != valhold:
Target.append(folder)
valhold=folder
create(valhold)
else:
valhold=folder
#a nested for loop which goes through all the files in the folder for the list "sourcefile"
#and finds a matching filename
for dst in Target:
wheretonumber=0
whereto = targetsrc(wheretonumber) #Name of folder for a given index value "targetsrc"
for file in list:
filenumber=0
filename=srcfile(filenumber) #Name of file for a given index value "sourcefile"
if file == dst:
##os.rename(filename(filenumber),whereto(wheretonumber))
##shutil.move(filename,whereto)
filenumber= filenumber+1
wheretonumber=wheretonumber+1
我能够做的第一两件事在我的项目符号列表上方，但有一个很难得到第三一个工作。 我看着shutil.move，os.path.walk和os.rename功能和有没有运气让他们工作。 我不断收到错误：
向其中加入= targetsrc（wheretonumber）类型错误：名单'对象不是可调用
我有os.rename和shutil.move注释掉了，因为我想不同的功能。 是我的逻辑的方法正确还是我失去了一些东西？ 在其他功能的任何建议，尝试或改变我的代码得到它的文件移动到一个文件夹？
