How do you deal with numbers larger than UInt64 (C

2019-01-14 16:42发布

问题:

In C#, how can one store and calculate with numbers that significantly exceed UInt64's max value (18,446,744,073,709,551,615)?

回答1:

By using a BigInteger class; there's one in the the J# libraries (definitely accessible from C#), another in F# (need to test this one), and there are freestanding implementations such as this one in pure C#.



回答2:

Can you use the .NET 4.0 beta? If so, you can use BigInteger.

Otherwise, if you're sticking within 28 digits, you can use decimal - but be aware that obviously that's going to perform decimal arithmetic, so you may need to round at various places to compensate.



回答3:

What is it that you wish to use these numbers for? If you are doing calculations with really big numbers, do you still need the accuracy down to the last digit? If not, you should consider using floating point values instead. They can be huge, the max value for the double type is 1.79769313486231570E+308, (in case you are not used to scientific notation it means 1.79769313486231570 multiplied by 10000000...0000 - 308 zeros).

That should be large enough for most applications



回答4:

BigInteger represents an arbitrarily large signed integer.

using System.Numerics;

var a = BigInteger.Parse("91389681247993671255432112000000");
var b = new BigInteger(1790322312);
var c = a * b;


回答5:

Decimal has greater range.

There is support for bigInteger in .NET 4.0 but that is still not out of beta.



回答6:

There are several libraries for computing with big integers, most of the cryptography libraries also offer a class for that. See this for a free library.



回答7:

You can use decimal. It is greater than Int64.

It has 28-29 significant digits.