I have a program, sink.py, that I want to run in a bash script (run.sh). sink.py needs data from stdin to do its job.
I'd like to feed data from another program, source.py, into sink.py. The following pipeline works fine:
python source.py | python sink.py
However, I'm looking to exec sink.py, so that it takes over the shell. I want to do this because I'm starting this bash script from a process manager (supervisord) and sink.py has all the signal handling code. So ideally I could do something like this:
python source.py | exec python sink.py
But this doesn't seem to work -- ps shows that run.sh continues to run as a parent of sink.py.
I tried using process substitution like this:
exec python sink.py < <(python source.py)
This is almost perfect, except the bash script appears to become a "zombie", which presumably is not a good thing:
PID TTY STAT TIME COMMAND
1042 pts/7 S 0:00 python sink.py
1046 pts/7 Z 0:00 [run.sh] <defunct>
One other thought I had was to just save the output of source.py into a temporary file, then direct the file into sink.py. That almost works, except I have no way of deleting the temp file once I exec sink.py.
Is there any good way to accomplish this?
