struct Point {
x: f64,
y: f64,
}
enum Shape {
Circle(Point, f64),
Rectangle(Point, Point),
}
let my_shape = Shape::Circle(Point { x: 0.0, y: 0.0 }, 10.0);
I want to print out circle
's second property, which is 10.0 here.
I tried my_shape.last
and my_shape.second
, but neither worked.
What should I do in order to print out 10.0 in this case?
You can use pattern matching:
struct Point {
x: f64,
y: f64,
}
enum Shape {
Circle(Point, f64),
Rectangle(Point, Point),
}
fn main() {
let my_shape = Shape::Circle(Point { x: 0.0, y: 0.0 }, 10.0);
match my_shape {
Shape::Circle(_, value) => println!("value: {}", value),
_ => println!("Something else"),
}
}
Example output:
value: 10
As you are only interested in matching one of the variants, you can use an if let
expression instead of a match
:
struct Point {
x: f64,
y: f64,
}
enum Shape {
Circle(Point, f64),
Rectangle(Point, Point),
}
fn main() {
let my_shape = Shape::Circle(Point { x: 0.0, y: 0.0 }, 10.0);
if let Shape::Circle(_, radius) = my_shape {
println!("value: {}", radius);
}
}
This means "if my_shape
can be destructured into a Circle
, do nothing with the first index, but bind the value of the second index to radius
".
From The Rust Programming Language:
Another useful feature of match arms is that they can bind to parts of the values that match the pattern. This is how we can extract values out of enum variants.
[...]
fn value_in_cents(coin: Coin) -> u32 {
match coin {
Coin::Penny => 1,
Coin::Nickel => 5,
Coin::Dime => 10,
Coin::Quarter(state) => {
println!("State quarter from {:?}!", state);
25
},
}
}
If you'd like to be able to write functions that are capable of working on multiple types with different representations, have a look at traits.
Here is another way to do it:
struct Point {
x: f64,
y: f64,
}
enum Shape {
Circle(Point, f64),
}
fn main() {
let Shape::Circle(_, radius) = Shape::Circle(Point { x: 0.0, y: 0.0 }, 10.0);
println!("value: {}", radius);
}
This only works if the pattern is irrefutable, such as when the enum type you're matching on only has one variant. To make this work, I had to remove the unused Rectangle
variant.
In cases where you have more than one variant, you'll probably want the full match expression anyway, since you're presumably handling more than just one kind of shape.