我有映射到其它3个表组合键遗留表中,由于该表有它的其他属性,因为它不是简单的映射表,我不能使用许多对多组溶液映射此。
下面是我做了什么:
<class name="classA" table="A">
<composite-id name="ID" class="AKey">
<key-many-to-one name="Id_one" class="One" column="Id_one" />
<key-many-to-one name="Id_two" class="Two" column="Id_two" />
<key-many-to-one name="Id_three" class="Three" column="Id_three" />
</composite-id>
AKEY仅仅是保持该三个ID,和Id_one,Id_two,和Id_three都被定义为在各自的类int一个结构。
public struct Akey {
public int Id_one { get; set; }
public int Id_two { get; set; }
public int Id_three { get; set; }
}
编译没有问题,但是当我尝试运行它,它给了我一个错误信息:
NHibernate.QueryException:在NHibernate.Criterion.SimpleExpression类型不匹配:ID预期型AKEY,实际类型System.Int32
请我做了什么错误或遗漏提出建议。
多谢!
如果你要使用钥匙多到一个你会把类:
public class Akey {
public virtual One One {get; set;}
public virtual Two Two {get; set;}
public virtual Three Three {get; set;}
}
否则,如果你想要的ID您只是把它们映射成为CLASSA的属性:
<composite-id>
<key-property name="Id_one" column="Id_one" />
<key-property name="Id_two" column="Id_two" />
<key-property name="Id_three" column="Id_three" />
</composite-id>
。
public class classA {
public virtual int Id_one {get; set;}
public virtual int Id_two {get; set;}
public virtual int Id_three {get; set;}
// ... rest of props ...
}
或者像你这样的组合有:
<composite-id name="ID" class="AKey">
<key-property name="Id_one" column="Id_one" />
<key-property name="Id_two" column="Id_two" />
<key-property name="Id_three" column="Id_three" />
</composite-id>
。
public class AKey {
public virtual int Id_one {get; set;}
public virtual int Id_two {get; set;}
public virtual int Id_three {get; set;}
}
public class classA {
public virtual AKey ID {get; set;}
// ... rest of props ...
}
最后...
<composite-id>
<key-many-to-one name="Id_one" class="One" column="Id_one" />
<key-many-to-one name="Id_two" class="Two" column="Id_two" />
<key-many-to-one name="Id_three" class="Three" column="Id_three" />
</composite-id>
。
public class classA {
public virtual One One {get; set;}
public virtual Two Two {get; set;}
public virtual Three Three {get; set;}
// ... rest of props ...
}
要踢你是否能使用结构,因为我不是在C#胜任他们。