问题:

This question already has an answer here:

Check if every element in one array is in a second array 9 answers

In JavaScript, how do I test that one array has the elements of another array?

arr1 = [1, 2, 3, 4, 5]
[8, 1, 10, 2, 3, 4, 5, 9].function_name(arr1) # => true

回答1:

No set function does this, but you can simply do an ad-hoc array intersection and check the length.

[8, 1, 10, 2, 3, 4, 5, 9].filter(function (elem) {
    return arr1.indexOf(elem) > -1;
}).length == arr1.length

A more efficient way to do this would be to use .every which will short circuit in falsey cases.

arr1.every(elem => arr2.indexOf(elem) > -1);

回答2:

You can use array.indexOf():

pseudocode:

function arrayContainsAnotherArray(needle, haystack){
  for(var i = 0; i < needle.length; i++){
    if(haystack.indexOf(needle[i]) === -1)
       return false;
  }
  return true;
}

回答3:

function arr(arr1,arr2)
{
    for(var i=0;i<arr1.length;i++)
     {
        if($.inArray(arr1[i],arr2) ==-1)
               //here it returns that arr1 value does not contain the arr2
        else
             // here it returns that arr1 value contains in arr2

     }

}