检查是否给定的日期范围内的日期之间的配合(Checking if a given date fits

如果我有一个表，2个日期列startDate和endDate 。 如何返回行，其中一个给定日期的2个日期之间的配合？ 例如：

如果给定的日期是2012-10-25

它应该返回下面的行

startDate   -   endDate
2012-10-25  -   2012-10-25
2011-09-10  -   2013-11-15
2012-10-20  -   2012-10-25
2012-10-23  -   2012-10-28
2012-09-14  -   2012-10-28

从以下行：

startDate   -   endDate
2012-10-25  -   2012-10-25
2011-09-10  -   2013-11-15
2012-01-11  -   2012-10-11
2012-10-20  -   2012-10-25
2012-04-15  -   2012-04-16
2012-05-20  -   2012-05-25
2012-12-01  -   2012-12-10
2012-10-23  -   2012-10-28
2012-09-14  -   2012-10-28
2012-11-13  -   2012-12-15

这可能与SQL？

我使用SQL Server 2008。

Answer 1:

在SQL Server，它实际上就这么简单：

SELECT startDate, endDate
FROM YourTable
WHERE '2012-10-25' between startDate and endDate

Answer 2:

检查之间的关键词。

语法很简单：

SELECT col1, col2
FROM table1
WHERE date_col BETWEEN '2012-10-25' and 2012-10-28

Answer 3:

其他lappingcheck以下可能是有趣

Select * from sted where [dbo].[F_LappingDays](Startdate,EndDate,'20121025','20121025')=1


CREATE Function [dbo].[F_LappingDays](@Von1 datetime,@bis1 Datetime,@von2 Datetime,@bis2 Datetime) Returns int as
/*
20110531 Thomas Wassermann
Terminüberschneidungen finden
*/
begin
Declare @Result int

Select @Result  = 0
if (@Von1>=@Von2) and (@bis1<=@Bis2)
    begin
        Select @Result=Cast(@Bis1 - @von1 + 1 as Int)
    end

else if (@Von1<=@Von2) and (@bis1 > @Von2) and (@bis1<=@Bis2)
    begin
        Select @Result=Cast(@Bis1 - @von2 + 1 as Int)
    end

else if (@Von1>=@Von2) and (@von1<=@bis2) and (@bis1>@Bis2)
    begin
        Select @Result=Cast(@Bis2 - @von1 + 1 as Int)
    end

else if (@Von1<@Von2) and (@bis1>@Bis2)
    begin
        Select @Result=Cast(@Bis2 - @von2 + 1 as Int)
    end



Return @Result
end 

文章来源: Checking if a given date fits between a range of dates