Checking file size in a batch script

问题:

I am trying to find the size of a file and if it is greater than 0, I want to do some stuff. I have this code:

set file="C:\AnalyzerCheck\loaded.txt"
set minbytesize=0
if exist %file% (
FOR /F "usebackq" %A IN ('%file%') DO set size=%~zA
if %size% GTR %minbytesize% (
    //do stuff
) else (
    //do stuff
)

However, I am getting this ouput/error when I run the script:

C:\AnalyzerCheck>set file=C:\AnalyzerCheck\loaded.txt

C:\AnalyzerCheck>set minbytesize=0

file~zA was unexpected at this time.

C:\AnalyzerCheck>FOR /F "usebackq" file~zA

C:\AnalyzerCheck>

How do I fix this error?

Edit:

New error:

回答1:

This command:

FOR /F "usebackq" %A IN ('%file%') DO set size=%~zA

have two errors: You must not use /F option (neither "useback" option) because you want not to read the file CONTENTS, but just process the file NAME. Also, if this command is inside a Batch file, the A replaceable parameter must have two percent signs:

FOR %%A IN (%file%) DO set size=%%~zA

回答2:

Within a scipt,

This Command:

    for /f %%A in ("myfile.txt") do set size=%%~zA

Or This Command:

    set "filename=myfile.txt"
    for %%A in (%filename%) do echo.Size of "%%A" is %%~zA bytes

Or This Command:

    set "filename=myfile.txt"
    for /f %%A in (%filename%) do set size=%%~zA

回答3:

@echo off
cd C:\MyFolder\
set file="MyFile.txt"

set maxbytesize=0

FOR /F "usebackq" %%A IN ('%file%') DO set size=%%~zA

if %size% GTR %maxbytesize% (
    //do stuff
) ELSE (
    //do stuff
)