I have a XMLLike this
<GLLines DataTypeID="GEN" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<GLLine>
<SYS_COMPANY_CODE>NB</SYS_COMPANY_CODE>
<ACCT_DOC_NUM>12720829</ACCT_DOC_NUM>
<ACCT_DOC_LINE>22114739</ACCT_DOC_LINE>
</GLLine>
<GLLine>
<SYS_COMPANY_CODE>NB</SYS_COMPANY_CODE>
<ACCT_DOC_NUM>12720827</ACCT_DOC_NUM>
<ACCT_DOC_LINE>22114740</ACCT_DOC_LINE>
</GLLine>
<GLLine>
<SYS_COMPANY_CODE>NB</SYS_COMPANY_CODE>
<ACCT_DOC_NUM>12720830</ACCT_DOC_NUM>
<ACCT_DOC_LINE>22114739</ACCT_DOC_LINE>
</GLLine>
<GLLine>
<SYS_COMPANY_CODE>NB</SYS_COMPANY_CODE>
<ACCT_DOC_NUM>12720830</ACCT_DOC_NUM>
<ACCT_DOC_LINE>22114738</ACCT_DOC_LINE>
</GLLine>
</GLLines>
I want to sort according to the acct DOC NUM and acct doc line .I tried XSLT but I don't know how to do it .so I'm getting wrong answer
Start with an identity transformation that just copies the input to output unchanged.
<xsl:template match="@*|node()">
<xsl:copy><xsl:apply-templates select="@*|node()" /></xsl:copy>
</xsl:template>
Now you can add a specific template for the GLLines
element to sort its children
<xsl:template match="GLLines">
<xsl:copy>
<xsl:apply-templates select="GLLine">
<!-- sort first on the ACCT_DOC_NUM -->
<xsl:sort select="ACCT_DOC_NUM" data-type="number" order="ascending" />
<!-- for lines with the same doc num, sort by line -->
<xsl:sort select="ACCT_DOC_LINE" data-type="number" order="ascending" />
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
Try this:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" omit-xml-declaration="no"/>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()">
<xsl:sort select="ACCT_DOC_NUM"/>
</xsl:apply-templates>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>