How to reference python package when filename cont

问题:

I am using django and I have a file named models.admin.py and I want to do the following idea in models.py:

from "models.admin" import *

however, I get a syntax error for having double quotes. But if I just do

from models.admin import *

then I get "ImportError: No module named admin"

Is there any way to import from a python file that has a period in its name?

回答1:

Actually, you can import a module with an invalid name. But you'll need to use imp for that, e.g. assuming file is named models.admin.py, you could do

import imp
with open('models.admin.py', 'rb') as fp:
    models_admin = imp.load_module(
        'models_admin', fp, 'models.admin.py',
        ('.py', 'rb', imp.PY_SOURCE)
    )

But read the docs on imp.find_module and imp.load_module before you start using it.

回答2:

If you really want to, you can import a module with an unusual filename (e.g., a filename containing a '.' before the '.py') using the imp module:

>>> import imp
>>> a_b = imp.load_source('a.b', 'a.b.py')
>>> a_b.x
"I was defined in a.b.py!"

However, that's generally a bad idea. It's more likely that you're trying to use packages, in which case you should create a directory named "a", containing a file named "b.py"; and then "import a.b" will load a/b.py.

回答3:

The file is called models/admin.py. (Source)

That is, it should be called admin.py in a directory called models.

Then you can import using from models.admin import *, assuming that it is in your Python path.

回答4:

No, you can't import a python file as a module if its name contains a period (or a question mark, or exclamation mark, etc). A python module's name (not including the .py) must be a valid python name (ie can be used as a variable name).

回答5:

You are not referencing files in the import statement, you are referencing modules and packages.

Please read the docs, they are very clear on that matter.

Anyway, since you are using django, the usual approach won't work. If you want to keep models in separate files, rather than in models.py, you have to take extra steps, outlined, for example, here.

Edit:
Well, I don't really know what the questioneer means when he mentions admin and whether or not it is related to the admin interface of django. My points still stand.