PHP - Issues removing “\\r\\n\\r\\n” from this str

2019-08-01 08:54发布

问题:

I start out with a string like this : "I would like to:\r\n\r\n1.) Rid this mess\r\n\r\n\2.) Now Please" (this is 'cleaned' user input text).

So essentially my statement would be this :

$query = sanitize($_POST['query']); // gives the result string

I want to remove the "\r\n\r\n"'s from this string. So far I have try to do this by using the following :

$query = preg_replace("/\r\n\r\n/", " ", $query);

or

$query = str_replace("\r\n\r\n", " ", $query);

None seem to work?

However, if I do the following :

$query = "I would like to:\r\n\r\n1.) Rid this mess\r\n\r\n\2.) Now Please";
$query = preg_replace("/\r\n\r\n/", " ", $query); // I tried str_replace() too
var_dump($query);
exit;

I get the output that I desire...

Could someone please explain to me why on earth this is happening and how i could solve the issue?

Any advice, input or suggestions would be greatly appreciated as I am not almost bald from pulling my hair out...

Thank you!

EDIT :

This may help function sanitize() :

function html($text)
{
    return htmlspecialchars($text, ENT_QUOTES, 'UTF-8');
}

function htmlout($text)
{
    return html($text);
}

function cleanInput($input)
{
    $search = array(
        '@<script[^>]*?>.*?</script>@si',   // Strip out javascript
        '@<[\/\!]*?[^<>]*?>@si',            // Strip out HTML tags
        '@<style[^>]*?>.*?</style>@siU',    // Strip style tags properly
        '@<![\s\S]*?--[ \t\n\r]*>@'         // Strip multi-line comments
    );
    $output = preg_replace($search, '', $input);
    $output  = htmlout($output);
    return $output;
}

function sanitize($input)
{
    if (is_array($input))
    {
        foreach($input as $var=>$val)
        {
            $output[$var] = sanitize($val);
        }
    }
    else
    {
        include "C:/wamp/www/includes/inc/main/db.inc.php";
        if (get_magic_quotes_gpc())
        {
            $input = stripslashes($input);
        }
        $input  = cleanInput($input);
        $output = mysqli_real_escape_string($link, $input);
    }
    return $output;
}

回答1:

The only proper solution

  1. Get rid of sanitize() function
  2. Use prepared statements to put your data into database.
  3. use htmlout() function to display user's text back.

You can read more here and here



回答2:

Have you got magic quotes on?

http://php.net/manual/en/info.configuration.php#ini.magic-quotes-gpc

It might be escaping your slashes.



回答3:

If there's literal \r\n characters in your database, you need to quadruple the slashes.

So you using this should in theory do the trick:

$query = preg_replace("/\\\\r\\\\n\\\\r\\\\n", " ", $query);


回答4:

This worked for me

$string = preg_replace("/\\\\r\\\\n\\\\r\\\\n/", "", $string);