I start out with a string like this : "I would like to:\r\n\r\n1.) Rid this mess\r\n\r\n\2.) Now Please" (this is 'cleaned' user input text).
So essentially my statement would be this :
$query = sanitize($_POST['query']); // gives the result string
I want to remove the "\r\n\r\n"'s from this string. So far I have try to do this by using the following :
$query = preg_replace("/\r\n\r\n/", " ", $query);
or
$query = str_replace("\r\n\r\n", " ", $query);
None seem to work?
However, if I do the following :
$query = "I would like to:\r\n\r\n1.) Rid this mess\r\n\r\n\2.) Now Please";
$query = preg_replace("/\r\n\r\n/", " ", $query); // I tried str_replace() too
var_dump($query);
exit;
I get the output that I desire...
Could someone please explain to me why on earth this is happening and how i could solve the issue?
Any advice, input or suggestions would be greatly appreciated as I am not almost bald from pulling my hair out...
Thank you!
EDIT :
This may help function sanitize() :
function html($text)
{
return htmlspecialchars($text, ENT_QUOTES, 'UTF-8');
}
function htmlout($text)
{
return html($text);
}
function cleanInput($input)
{
$search = array(
'@<script[^>]*?>.*?</script>@si', // Strip out javascript
'@<[\/\!]*?[^<>]*?>@si', // Strip out HTML tags
'@<style[^>]*?>.*?</style>@siU', // Strip style tags properly
'@<![\s\S]*?--[ \t\n\r]*>@' // Strip multi-line comments
);
$output = preg_replace($search, '', $input);
$output = htmlout($output);
return $output;
}
function sanitize($input)
{
if (is_array($input))
{
foreach($input as $var=>$val)
{
$output[$var] = sanitize($val);
}
}
else
{
include "C:/wamp/www/includes/inc/main/db.inc.php";
if (get_magic_quotes_gpc())
{
$input = stripslashes($input);
}
$input = cleanInput($input);
$output = mysqli_real_escape_string($link, $input);
}
return $output;
}