0条评论
还没有人评论过~
#include<iostream> using namespace std; template<typename T> class Code; //友元函数的声明; template<typename T> ostream& operator<< (ostream& , Code<T>&); template<typename T> class Code { public: friend ostream& operator << <T>(ostream& out, const Code<T>&code); Code() {data=10;} private: T data; }; //友元函数的实现; template<typename T> ostream& operator << (ostream& out, const Code<T>&code) { out << "data: " << code.data << endl; return out; } int main() { Code<int> d; cout<<d<<endl; return 0; }
错误信息:[Error] template-id 'operator<< <int>' for 'std::ostream& operator<<(std::ostream&, const Code<int>&)' does not match any template declaration
声明改成const Code&