UPDATE SET表1列1 =（SUM（表2 {＆表3}其中table2_id1 = ID1）WH

我想更新基于主要应用于对表2的，但包括从表3的单个值的总和表1。

表2有真实FKD到表1的id列一列，总和是基于他们匹配。

UPDATE table1, table2 
SET table1.column1 = 
(SELECT SUM( (SELECT constant FROM table3) +
          (SELECT table2.sum_number 
           WHERE table2.table2_id1 = table1.id) ) ) 
WHERE table1.id = table2.table2_id1;

这并不为我工作。

提前谢谢了！

编辑：错误假设

#1064 - You have an error in your SQL syntax; check the manual that corresponds 
 to your MySQL server version for the right syntax to use near 
 'WHERE table2.table2_id1 = table1.id) ) ) WHERE table1.id = table2.table2_id1;'

Answer 1:

UPDATE table1, table2 
SET table1.column1 = 
(
    SELECT SUM( 
        (SELECT constant FROM table3) +
        (SELECT table2.sum_number *** WHERE table2.table2_id1 = table1.id) 
    ) 
) 
WHERE table1.id = table2.table2_id1;

有没有“FROM表2，表1”，在标有上述astericks的区域。

Answer 2:

试试这个：

UPDATE 
    table1 t1
INNER JOIN
    table2 t2 ON t2.table2_id1 = t1.id
SET
    t1.column1 = (SELECT constant FROM table3) + t2.sum_number

Answer 3:

试试这个：

Update table1 t1 join table2 t2 on t1.id = t2.table2_id1
SET t1.column1 = (SELECT constant FROM table3) + t2.sum_number

文章来源: UPDATE table1 SET column1 = (SUM(table2{& table3} WHERE table2_id1 = id1) WHERE id1 = table2_id1