我有点坚持了为什么我似乎无法得到插入行的“新身份”与下面的语句。 SCOPE_IDENTITY()
刚刚返回null。
declare @WorkRequestQueueID int
declare @LastException nvarchar(MAX)
set @WorkRequestQueueID = 1
set @LastException = 'test'
set nocount off
DELETE dbo.WorkRequestQueue
OUTPUT
DELETED.MessageEnvelope,
DELETED.Attempts,
@LastException,
GetUtcdate(), -- WorkItemPoisened datetime
DELETED.WorkItemReceived_UTC
INTO dbo.FaildMessages
FROM dbo.WorkRequestQueue
WHERE
WorkRequestQueue.ID = @WorkRequestQueueID
IF @@ROWCOUNT = 0
RAISERROR ('Record not found', 16, 1)
SELECT Cast(SCOPE_IDENTITY() as int)
任何援助将非常感激。
现在我用这个解决方法,像这样。
declare @WorkRequestQueueID int
declare @LastException nvarchar(MAX)
set @WorkRequestQueueID = 7
set @LastException = 'test'
set nocount on
set xact_abort on
DECLARE @Failed TABLE
(
MessageEnvelope xml,
Attempts smallint,
LastException nvarchar(max),
WorkItemPoisened_UTC datetime,
WorkItemReceived_UTC datetime
)
BEGIN TRAN
DELETE dbo.WorkRequestQueue
OUTPUT
DELETED.MessageEnvelope,
DELETED.Attempts,
@LastException,
GetUtcdate(), -- WorkItemPoisened datetime
DELETED.WorkItemReceived_UTC
INTO
@Failed
FROM
dbo.WorkRequestQueue
WHERE
WorkRequestQueue.ID = @WorkRequestQueueID
IF @@ROWCOUNT = 0 BEGIN
RAISERROR ('Record not found', 16, 1)
Rollback
END ELSE BEGIN
insert into dbo.FaildMessages select * from @Failed
COMMIT TRAN
SELECT Cast(SCOPE_IDENTITY() as int)
END
你可以尝试使用表变量为您output
条款,从而使您可以明确地插入FaildMessages
:
declare @WorkRequestQueueID int
declare @LastException nvarchar(MAX)
set @WorkRequestQueueID = 1
set @LastException = 'test'
set nocount off
-- Declare a table variable to capture output
DECLARE @output TABLE (
MessageEnvelope VARCHAR(50), -- Guessing at datatypes
Attempts INT, -- Guessing at datatypes
WorkItemReceived_UTC DATETIME -- Guessing at datatypes
)
-- Run the deletion with output
DELETE dbo.WorkRequestQueue
OUTPUT
DELETED.MessageEnvelope,
DELETED.Attempts,
DELETED.WorkItemReceived_UTC
-- Use the table var
INTO @output
FROM dbo.WorkRequestQueue
WHERE
WorkRequestQueue.ID = @WorkRequestQueueID
-- Explicitly insert
INSERT
INTO dbo.FaildMessages
SELECT
MessageEnvelope,
Attempts,
@LastException,
GetUtcdate(), -- WorkItemPoisened datetime
WorkItemReceived_UTC
FROM @output
IF @@ROWCOUNT = 0
RAISERROR ('Record not found', 16, 1)
SELECT Cast(SCOPE_IDENTITY() as int)
EDITED FEB'2013
@MartinSmith提醒我们,这个错误不希望被微软定 。
“发布Microsoft在2013年2月27日在下午2时18分您好马丁,我们调查这个问题,并发现,改变的行为不是一件容易的事。这将基本上都需要进行重新定义一些行为当两个INSERT和输出的。INTO目标具有标识列鉴于问题和不凡的情形的性质,我们已经决定不解决这个问题 - Umachandar,SQL可编程性团队”
EDITED OCT'2012
这是由错误引起的:
测试错误:
引用OUTPUT子句文档 :
只有嵌套DML语句生成@@ IDENTITY,SCOPE_IDENTITY和IDENT_CURRENT返回标识值,而不是那些由外部INSERT语句生成。
测试后,它似乎SCOPE_IDENTITY()只有当外部运行与身份列的表的插入的工作原理:
测试1:删除
create table #t ( a char(1) );
create table #d ( a char(1), i int identity );
insert into #t
values ('a'),('b'),('c');
delete #t
output deleted.a into #d;
select SCOPE_IDENTITY(), * from #d;
a i
---- - -
null a 1
null b 2
null c 3
测试2: 与身份外表中插入
create table #t ( a char(1), i int identity );
create table #d ( a char(1), i int identity );
insert into #t
values ('x'),('x'),('x');
insert into #t
output inserted.a into #d
values ('a'),('b');
select scope_identity(), * from #d;
a i
- - -
2 a 1
2 b 2
测试3:无标识外表中插入
create table #t ( a char(1) );
create table #d ( a char(1), i int identity );
insert into #t
values ('x'),('x'),('x');
insert into #t
output inserted.a into #d
values ('a'),('b');
select scope_identity(), * from #d;
a i
---- - -
null a 1
null b 2