罗马的XmlReader不读HTTPS饲料(Rome XmlReader not reading h

我想读https：//开头d3ca01230439ce08d4aab0c61810af23：[e-mail]/recordings.atom

使用罗马，但它给我的错误

   INFO: Illegal access: this web application instance has been stopped already.  Could not load org.bouncycastle.jcajce.provider.symmetric.AES$ECB.  The eventual following stack trace is caused by an error thrown for debugging purposes as well as to attempt to terminate the thread which caused the illegal access, and has no functional impact.

和

   Server returned HTTP response code: 401 for URL: https://d3ca01230439ce08d4aab0c61810af23:[e-mail]/recordings.atom .

我这样做

    URL url =  new URL("https://d3ca01230439ce08d4aab0c61810af23:[e-mail]/recordings.atom ");

    try {
    SyndFeedInput input = new SyndFeedInput();

        SyndFeed feed = input.build(new XmlReader(url));

        System.out.println("Feed Author:"+feed.getAuthor());

        for(Object entries: feed.getEntries()){

            SyndEntry entry = (SyndEntry) entries;

            System.out.println("title :"+entry.getTitle());
            System.out.println("description : "+entry.getDescription());

        }


    } catch (IllegalArgumentException | FeedException | IOException e) {
        e.printStackTrace();
    }

我需要把用户名密码的地方？

更新

这是我做了

  URL url =  new URL("https://d3ca01230439ce08d4aab0c61810af23:[e-mail]/recordings.atom");

    HttpURLConnection httpcon = (HttpURLConnection)url.openConnection();

    String encoding = new sun.misc.BASE64Encoder().encode("username:pass".getBytes());

    httpcon.setRequestProperty  ("Authorization", "Basic " + encoding);

Answer 1:

当我打的网址从我的浏览器，它要求基本身份验证。 您可以与罗马这样做：

URL feedUrl = new URL(feed)
HttpURLConnection httpcon = (HttpURLConnection)feedUrl.openConnection();
String encoding = new sun.misc.BASE64Encoder().encode("username:password".getBytes());
httpcon.setRequestProperty  ("Authorization", "Basic " + encoding);
SyndFeedInput input = new SyndFeedInput();
SyndFeed feed = input.build(new XmlReader(httpcon));

你可能不应该使用sun.misc.BASE64Encoder。 而是在某个地方找到另一个。

来源： http://cephas.net/blog/2005/02/09/retrieving-an-rss-feed-protected-by-basic-authentication-using-rome/

Answer 2:

我觉得这更有弹性一点，当涉及到身份验证，此代码的工作有和没有身份验证：

URL feedUrl = new URL("http://the.url.to/the/feed");
//URL feedUrl = new URL("http://user:[e-mail]/the/feed");

HttpURLConnection connection = (HttpURLConnection) feedUrl.openConnection();
if (feedUrl.getUserInfo() != null) {
    String encoding = new sun.misc.BASE64Encoder().encode(feedUrl.getUserInfo().getBytes());
    connection.setRequestProperty("Authorization", "Basic " + encoding);
}

SyndFeedInput input = new SyndFeedInput();
SyndFeed feed = input.build(new XmlReader(connection));

Answer 3:

你也可以使用以下代替

String encoding = new sun.misc.BASE64Encoder().encode("username:password".getBytes());

为此：

String BASIC_AUTH = "Basic " + Base64.encodeToString("username:password".getBytes(), Base64.NO_WRAP);

文章来源: Rome XmlReader not reading https feed