当开始bindService IntentService应onHandleIntent叫？(Shou

我的服务扩展IntentService并且当它开始startService ， onHandleIntent被调用。然而，当服务开始bindService （我确实需要结合）， onHandleIntent不会被调用。

应onHandleIntent时被称为IntentService开始与bindService ？是startService的唯一途径IntentService要开始了吗？

对于文档IntentService说以下内容：

客户端通过startService（意向）调用发送请求; 该服务已启动根据需要，处理使用一个工作线程按顺序将每意图，当它运行的工作停止本身。

目前，我通过调用解决我的问题startService之后bindService但我觉得它难看。我想知道有没有办法让它只用一个电话工作。

代码片段效仿，这也许是因为我失去了一些东西明显。

ExampleService.java

public class ExampleService extends IntentService {

private class IncomingHandler extends Handler {

    @Override
    public void handleMessage(Message message) {

        if (message.replyTo != null) {
            outMessenger = message.replyTo;
        }
    }
}

private Messenger messenger = new Messenger(new IncomingHandler()); 
private Messenger outMessenger = null;


public ExampleService() {
    super("ExampleService");
}

@Override
public IBinder onBind(Intent intent) {
    return messenger.getBinder();
}

@Override
protected void onHandleIntent(Intent arg0) {

    System.out.println("Service started");

    for (int i = 0; i < 5; i++) {

        SystemClock.sleep(5000);

        if (outMessenger != null) {
            try {
                outMessenger.send(Message.obtain());
            } catch (RemoteException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
        }
    }
}
}

服务的Manifest.xml

<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.example.service"
android:versionCode="1"
android:versionName="1.0" >

<uses-sdk
    android:minSdkVersion="3"
    android:targetSdkVersion="15" />

<application
    android:icon="@drawable/ic_launcher"
    android:label="@string/app_name"
    android:theme="@style/AppTheme" >
    <activity
        android:name=".MainActivity"
        android:label="@string/title_activity_main" >
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />

            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
    </activity>
    <service android:name=".ExampleService">
        <intent-filter>
            <action android:name="com.example.service.ExampleService" />
        </intent-filter>
    </service>
</application>
</manifest>

MainActivity.java（主叫）

public class MainActivity extends Activity implements ServiceConnection {


private class IncomingHandler extends Handler {

    @Override
    public void handleMessage(Message msg) {

        Toast.makeText(getApplicationContext(), "Message received", Toast.LENGTH_SHORT).show();
        System.out.println("Message received!");
        super.handleMessage(msg);
    }
}

private Messenger messenger = new Messenger(new IncomingHandler());

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    Button button = (Button) findViewById(R.id.button1);
    button.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {

            Intent intent = new Intent("com.example.service.ExampleService");
            bindService(intent, MainActivity.this, Context.BIND_AUTO_CREATE);
            //startService(intent);
        }
    });

}

@Override
public void onServiceConnected(ComponentName name, IBinder binder) {

    Message message = Message.obtain();
    message.replyTo = messenger;

    try {
        new Messenger(binder).send(message);
    } catch (RemoteException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}

@Override
public void onServiceDisconnected(ComponentName name) {
    // TODO Auto-generated method stub
}
}

Answer 1: