I wrote some statements like below:
os.system(cmd) #do something
subprocess.call(\'taskkill /F /IM exename.exe\')
both will pop up a console.
How can I stop it from popping up the console?
I wrote some statements like below:
os.system(cmd) #do something
subprocess.call(\'taskkill /F /IM exename.exe\')
both will pop up a console.
How can I stop it from popping up the console?
The process STARTUPINFO
can hide the console window:
si = subprocess.STARTUPINFO()
si.dwFlags |= subprocess.STARTF_USESHOWWINDOW
#si.wShowWindow = subprocess.SW_HIDE # default
subprocess.call(\'taskkill /F /IM exename.exe\', startupinfo=si)
Or set the creation flags to disable creating the window:
CREATE_NO_WINDOW = 0x08000000
subprocess.call(\'taskkill /F /IM exename.exe\', creationflags=CREATE_NO_WINDOW)
The above is still a console process with valid handles for console I/O (verified by calling GetFileType
on the handles returned by GetStdHandle
). It just has no window and doesn\'t inherit the parent\'s console, if any.
You can go a step farther by forcing the child to have no console at all:
DETACHED_PROCESS = 0x00000008
subprocess.call(\'taskkill /F /IM exename.exe\', creationflags=DETACHED_PROCESS)
In this case the child\'s standard handles (i.e. GetStdHandle
) are 0, but you can set them to an open disk file or pipe such as subprocess.DEVNULL
(3.3) or subprocess.PIPE
.
Add the shell=True
argument to the subprocess calls.
subprocess.call(\'taskkill /F /IM exename.exe\', shell=True)
Or, if you don\'t need to wait for it, use subprocess.Popen
rather than subprocess.call
.
subprocess.Popen(\'taskkill /F /IM exename.exe\', shell=True)
try to change the extension from .py to .pyw
Try subprocess.Popen([\"function\",\"option1\",\"option2\"],shell=False)
.