When I do...
ls$IFS-l
... I get the output I expect.
When I do...
curl$IFShttp://www.google.com
... I don't.
Am I misunderstanding internal field separators? How could I run a curl command without using any space characters?
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试):
问题:
回答1:
You need to put the variable within curly brackets, otherwise the shell looks for a variable called "IFShttp...":
curl${IFS}http://www.google.com
