如何获得与Java的HttpServer / HttpExchange一个GET查询字符串？(How

我试图创建一个简单的Java的HttpServer处理GET请求，但是当我试图让GET参数的请求，我注意到了HttpExchange类不具有该方法。

有谁知道一个简单的方法来读取GET参数（查询字符串）？

这是我的处理程序看起来像：

public class TestHandler{
  @Override
  public void handle(HttpExchange exc) throws IOxception {
    String response = "This is the reponse";
    exc.sendResponseHeaders(200, response.length());

    // need GET params here

    OutputStream os = exc.getResponseBody();
    os.write(response.getBytes());
    os.close();
  } 
}

..和主要方法：

public static void main(String[] args) throws Exception{
  // create server on port 8000
  InetSocketAddress address = new InetSocketAddress(8000);
  HttpServer server = new HttpServer.create(address, 0);

  // bind handler
  server.createContext("/highscore", new TestHandler());
  server.setExecutor(null);
  server.start();
}

Answer 1:

以下内容： httpExchange.getRequestURI().getQuery()

：将在类似这样的格式返回字符串"field1=value1&field2=value2&field3=value3..."

所以你可以简单地自己分析的字符串，这是多么的解析函数可能看起来像：

public Map<String, String> queryToMap(String query) {
    Map<String, String> result = new HashMap<>();
    for (String param : query.split("&")) {
        String[] entry = param.split("=");
        if (entry.length > 1) {
            result.put(entry[0], entry[1]);
        }else{
            result.put(entry[0], "");
        }
    }
    return result;
}

这是你如何使用它：

Map<String, String> params = queryToMap(httpExchange.getRequestURI().getQuery()); 
System.out.println("param A=" + params.get("A"));

Answer 2:

通过@ anon01对答案的基础上，这是如何做到这一点在Groovy：

Map<String,String> getQueryParameters( HttpExchange httpExchange )
{
    def query = httpExchange.getRequestURI().getQuery()
    return query.split( '&' )
            .collectEntries {
        String[] pair = it.split( '=' )
        if (pair.length > 1)
        {
            return [(pair[0]): pair[1]]
        }
        else
        {
            return [(pair[0]): ""]
        }
    }
}

这是如何使用它：

def queryParameters = getQueryParameters( httpExchange )
def parameterA = queryParameters['A']

Answer 3:

这个答案，相反annon01的，正确解码键和值。 它不使用String.split ，但使用扫描字符串indexOf ，这是更快。

public static Map<String, String> parseQueryString(String qs) {
    Map<String, String> result = new HashMap<>();
    if (qs == null)
        return result;

    int last = 0, next, l = qs.length();
    while (last < l) {
        next = qs.indexOf('&', last);
        if (next == -1)
            next = l;

        if (next > last) {
            int eqPos = qs.indexOf('=', last);
            try {
                if (eqPos < 0 || eqPos > next)
                    result.put(URLDecoder.decode(qs.substring(last, next), "utf-8"), "");
                else
                    result.put(URLDecoder.decode(qs.substring(last, eqPos), "utf-8"), URLDecoder.decode(qs.substring(eqPos + 1, next), "utf-8"));
            } catch (UnsupportedEncodingException e) {
                throw new RuntimeException(e); // will never happen, utf-8 support is mandatory for java
            }
        }
        last = next + 1;
    }
    return result;
}

文章来源: How to obtain the query string in a GET with Java HttpServer/HttpExchange?