MySQL Error: #1142 - SELECT command denied to user

问题:

I'm having troubles with a certain query on one of my servers. On all other places I've tested it it works completely fine but on the server i want to use it it isn't working.

It's about the following SQL:

SELECT facturen.id            AS fid, 
       projecten.id           AS pid, 
       titel, 
       facturen.totaal_bedrag AS totaal, 
       betaald, 
       datum 
FROM   facturen, 
       projecten 
WHERE  facturen.project_id = projecten.id 
       AND projecten.eigenaar = '1' 
ORDER  BY datum DESC 

This is the error code I get from it:

SELECT command denied to user 'marco'@'localhost' for table 'projecten'

The tables: facturen:

CREATE TABLE IF NOT EXISTS `facturen` (
  `id` int(11) NOT NULL auto_increment,
  `project_id` int(11) NOT NULL,
  `datum` int(11) NOT NULL,
  `lever_datum` int(11) NOT NULL,
  `totaal_bedrag` decimal(9,2) NOT NULL,
  `btw` decimal(9,2) NOT NULL,
  `bedrijf` varchar(40) NOT NULL,
  `contactpersoon` varchar(60) NOT NULL,
  `adres` varchar(60) NOT NULL,
  `postcode` varchar(7) NOT NULL,
  `plaats` varchar(30) NOT NULL,
  `betaald` int(11) NOT NULL,
  PRIMARY KEY  (`id`)
) ENGINE=MyISAM  DEFAULT CHARSET=latin1 AUTO_INCREMENT=201200006 ;

projecten:

CREATE TABLE IF NOT EXISTS `projecten` (
  `id` int(11) NOT NULL auto_increment,
  `titel` varchar(80) NOT NULL,
  `eigenaar` int(11) NOT NULL,
  `creatie_datum` int(11) NOT NULL,
  `eind_datum` int(11) NOT NULL,
  `totaal_bedrag` decimal(9,2) NOT NULL,
  `btw` decimal(9,2) NOT NULL,
  PRIMARY KEY  (`id`)
) ENGINE=MyISAM  DEFAULT CHARSET=latin1 AUTO_INCREMENT=201200004 ;

The strange part is that every other query on both the 'projecten' table and the 'facturen' table works completely fine, also this query works fine on two other servers of mine.

回答1:

You need to grant SELECT permissions to the MySQL user who is connecting to MySQL

same question as here Error: select command denied to user '<userid>'@'<ip-address>' for table '<table-name>'

see answers of the link ;)

回答2:

I faced the same situation but its funny that reason for the error was due to the use of the incorrect database or schema name.

Its true that multiple issues can lead to error you have mentioned.

回答3:

This error also arises for a syntax error occurred due to aliasing tablename.

For instance, when executed below query,

select * from a.table1, b.table2 where a.table1= b.table2

below error occurs:

MySQL Error: #1142. Response form the database. SELECT command denied to user "username@ip" for table "table1"

Solution : Syntax to alias tablename should be used proper, syntax solution for above instance >select * from table1 a, table2 b where a.table1= b.table2

回答4:

I had this problem too and for me, the problem was that I moved to a new server and the database I was trying to connect to with my PHP code changed from "my_Database" to "my_database".

回答5:

This is th privileges issue in your database users. first check and grant permission to user 'marco' in localhost

回答6:

So the issue I ran into was this... the application I used to grant the permissions converted the Schema.TableName into a single DB statement in the wrong table, so the grant was indeed wrong, but looked correct when we did a SHOW GRANTS FOR UserName if you weren't paying very close attention to GRANT SELECT vs GRANT TABLE SELECT. Manually correcting the Grant Select on Table w/ proper escaping of Schema.Table solved my issue.

May be unrelated, but I can imagine if one client does this wrong, another might too.

Hope that's helpful.

回答7:

In MySQL query browser go to Tools tab>MySQL Administrator > User Administration and then give the privileges to user.

回答8:

it's about the privallage of user in the mysql,so you should set the bigger grants with your users.

do this !

In the Terminal, put code mysql> show grants;

then change the following code like this :

GRANT ALL PRIVILEGES ON *.* TO 'root'@'localhost' IDENTIFIED BY PASSWORD '*3F9DF5A32114E05C12C50A83EAE02991016C917B' WITH GRANT OPTION;

Then it will be done.