我有一个大NSArray含有NSNumbers像3, 4, 20, 10, 1, 100,等...
我如何获得这些NSNumbers的总和(3 + 4 + 20 + 10 + 1 + 100 + etc...)作为一个总NSInteger ？
谢谢！
Answer 1:
NSInteger sum = 0;
for (NSNumber *num in myArray) {
sum += [num intValue];
}
Answer 2:
您可以使用此：
NSArray* numbers = //array of numbers
NSNumber* sum = [numbers valueForKeyPath: @"@sum.self"];
Answer 3:
long long sum = ((NSNumber*)[array valueForKeyPath: @"@sum.longLongValue"]).longLongValue;
Answer 4:
通过阵列迭代
int count = [array count];
NSInteger sum = 0;
for (int i = 0; i < count; i++) {
sum += [[array objectAtIndex:i] integerValue];
}
Answer 5:
[[numbersArray valueForKeyPath:@"@sum.self"] integerValue]
Answer 6:
int total = 0;
for (NSNumber *number in array)
{
total += [number intValue];
}
可能这将帮助你
文章来源: How get the total sum of NSNumber's from a NSArray?
