Browsers have practical limits on the number of arguments a function can take
You can change the sum
signature to accept an array rather than a varying number of arguments, and use destructuring to keep the syntax/readability similar to what you have. This "fixes" the stackoverflow error, but is increadibly slow :D
function _sum([num1, num2, ...nums]) { /* ... */ }
I.e.:, if you're running in to problems with maximum argument counts, your recursive/trampoline approach is probably going to be too slow to work with...
The other answer points out the limitation on number of function arguments, but I wanted to remark on your trampoline implementation. The long computation we're running may want to return a function. If you use typeof res === 'function'
, it's not longer possible to compute a function as a return value!
Instead, encode your trampoline variants with some sort of unique identifiers
const bounce = (f, ...args) =>
({ tag: bounce, f: f, args: args })
const done = (value) =>
({ tag: done, value: value })
const trampoline = t =>
{ while (t && t.tag === bounce)
t = t.f (...t.args)
if (t && t.tag === done)
return t.value
else
throw Error (`unsupported trampoline type: ${t.tag}`)
}
Before we hop on, let's first get an example function to fix
const none =
Symbol ()
const badsum = ([ n1, n2 = none, ...rest ]) =>
n2 === none
? n1
: badsum ([ n1 + n2, ...rest ])
We'll throw a range
of numbers at it to see it work
const range = n =>
Array.from
( Array (n + 1)
, (_, n) => n
)
console.log (range (10))
// [ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 ]
console.log (badsum (range (10)))
// 55
But can it handle the big leagues?
console.log (badsum (range (1000)))
// 500500
console.log (badsum (range (20000)))
// RangeError: Maximum call stack size exceeded
See the results in your browser so far
const none =
Symbol ()
const badsum = ([ n1, n2 = none, ...rest ]) =>
n2 === none
? n1
: badsum ([ n1 + n2, ...rest ])
const range = n =>
Array.from
( Array (n + 1)
, (_, n) => n
)
console.log (range (10))
// [ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 ]
console.log (badsum (range (1000)))
// 500500
console.log (badsum (range (20000)))
// RangeError: Maximum call stack size exceeded
Somewhere between 10000
and 20000
our badsum
function unsurprisingly causes a stack overflow.
Besides renaming the function to goodsum
we only have to encode the return types using our trampoline's variants
const goodsum = ([ n1, n2 = none, ...rest ]) =>
n2 === none
? n1
? done (n1)
: goodsum ([ n1 + n2, ...rest ])
: bounce (goodsum, [ n1 + n2, ...rest ])
console.log (trampoline (goodsum (range (1000))))
// 500500
console.log (trampoline (goodsum (range (20000))))
// 200010000
// No more stack overflow!
You can see the results of this program in your browser here. Now we can see that neither recursion nor the trampoline are at fault for this program being slow. Don't worry though, we'll fix that later.
const bounce = (f, ...args) =>
({ tag: bounce, f: f, args: args })
const done = (value) =>
({ tag: done, value: value })
const trampoline = t =>
{ while (t && t.tag === bounce)
t = t.f (...t.args)
if (t && t.tag === done)
return t.value
else
throw Error (`unsupported trampoline type: ${t.tag}`)
}
const none =
Symbol ()
const range = n =>
Array.from
( Array (n + 1)
, (_, n) => n
)
const goodsum = ([ n1, n2 = none, ...rest ]) =>
n2 === none
? done (n1)
: bounce (goodsum, [ n1 + n2, ...rest ])
console.log (trampoline (goodsum (range (1000))))
// 500500
console.log (trampoline (goodsum (range (20000))))
// 200010000
// No more stack overflow!
The extra call to trampoline
can get annoying, and when you look at goodsum
alone, it's not immediately apparent what done
and bounce
are doing there, unless maybe this was a very common convention in many of your programs.
We can better encode our looping intentions with a generic loop
function. A loop is given a function that is recalled whenever the function calls recur
. It looks like a recursive call, but really recur
is constructing a value that loop
handles in a stack-safe way.
The function we give to loop
can have any number of parameters, and with default values. This is also convenient because we can now avoid the expensive ...
destructuring and spreading by simply using an index parameter i
initialized to 0
. The caller of the function does not have the ability to access these variables outside of the loop call
The last advantage here is that the reader of goodsum
can clearly see the loop encoding and the explicit done
tag is no longer necessary. The user of the function does not need to worry about calling trampoline
either as it's already taken care of for us in loop
const goodsum = (ns = []) =>
loop ((sum = 0, i = 0) =>
i >= ns.length
? sum
: recur (sum + ns[i], i + 1))
console.log (goodsum (range (1000)))
// 500500
console.log (goodsum (range (20000)))
// 200010000
console.log (goodsum (range (999999)))
// 499999500000
Here's our loop
and recur
pair now. This time we expand upon our { tag: ... }
convention using a tagging module
const recur = (...values) =>
tag (recur, { values })
const loop = f =>
{ let acc = f ()
while (is (recur, acc))
acc = f (...acc.values)
return acc
}
const T =
Symbol ()
const tag = (t, x) =>
Object.assign (x, { [T]: t })
const is = (t, x) =>
t && x[T] === t
Run it in your browser to verify the results
const T =
Symbol ()
const tag = (t, x) =>
Object.assign (x, { [T]: t })
const is = (t, x) =>
t && x[T] === t
const recur = (...values) =>
tag (recur, { values })
const loop = f =>
{ let acc = f ()
while (is (recur, acc))
acc = f (...acc.values)
return acc
}
const range = n =>
Array.from
( Array (n + 1)
, (_, n) => n
)
const goodsum = (ns = []) =>
loop ((sum = 0, i = 0) =>
i >= ns.length
? sum
: recur (sum + ns[i], i + 1))
console.log (goodsum (range (1000)))
// 500500
console.log (goodsum (range (20000)))
// 200010000
console.log (goodsum (range (999999)))
// 499999500000
extra
My brain has been stuck in anamorphism gear for a few months and I was curious if it was possible to implement a stack-safe unfold
using the loop
function introduced above
Below, we look at an example program which generates the entire sequence of sums up to n
. Think of it as showing the work to arrive at the answer for the goodsum
program above. The total sum up to n
is the last element in the array.
This is a good use case for unfold
. We could write this using loop
directly, but the point of this was to stretch the limits of unfold
so here goes
const sumseq = (n = 0) =>
unfold
( (loop, done, [ m, sum ]) =>
m > n
? done ()
: loop (sum, [ m + 1, sum + m ])
, [ 1, 0 ]
)
console.log (sumseq (10))
// [ 0, 1, 3, 6, 10, 15, 21, 28, 36, 45 ]
// +1 ↗ +2 ↗ +3 ↗ +4 ↗ +5 ↗ +6 ↗ +7 ↗ +8 ↗ +9 ↗ ...
If we used an unsafe unfold
implementation, we could blow the stack
// direct recursion, stack-unsafe!
const unfold = (f, initState) =>
f ( (x, nextState) => [ x, ...unfold (f, nextState) ]
, () => []
, initState
)
console.log (sumseq (20000))
// RangeError: Maximum call stack size exceeded
After playing with it a little bit, it is indeed possible to encode unfold
using our stack-safe loop
. Cleaning up the ...
spread syntax using a push
effect makes things a lot quicker too
const push = (xs, x) =>
(xs .push (x), xs)
const unfold = (f, init) =>
loop ((acc = [], state = init) =>
f ( (x, nextState) => recur (push (acc, x), nextState)
, () => acc
, state
))
With a stack-safe unfold
, our sumseq
function works a treat now
console.time ('sumseq')
const result = sumseq (20000)
console.timeEnd ('sumseq')
console.log (result)
// sumseq: 23 ms
// [ 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, ..., 199990000 ]
Verify the result in your browser below
const recur = (...values) =>
tag (recur, { values })
const loop = f =>
{ let acc = f ()
while (is (recur, acc))
acc = f (...acc.values)
return acc
}
const T =
Symbol ()
const tag = (t, x) =>
Object.assign (x, { [T]: t })
const is = (t, x) =>
t && x[T] === t
const push = (xs, x) =>
(xs .push (x), xs)
const unfold = (f, init) =>
loop ((acc = [], state = init) =>
f ( (x, nextState) => recur (push (acc, x), nextState)
, () => acc
, state
))
const sumseq = (n = 0) =>
unfold
( (loop, done, [ m, sum ]) =>
m > n
? done ()
: loop (sum, [ m + 1, sum + m ])
, [ 1, 0 ]
)
console.time ('sumseq')
const result = sumseq (20000)
console.timeEnd ('sumseq')
console.log (result)
// sumseq: 23 ms
// [ 0, 1, 3, 6, 10, 15, 21, 28, 36, 45, ..., 199990000 ]