如何防止打印相同的结果,这两次查询?(How to prevent this query from

2019-07-29 08:27发布

我设法创建一个适合我的需要的查询。 但现在我遇到了在那里给出的显示结果的方式目前查询重复每一个结果两次的问题。 我怎样才能使它正常工作,它显示了它一次。

码:

$sql = "SELECT DISTINCT contacts.contact_id, user_accounts.full_name, 
contact_notes.note_name, contact_notes.type, contact_notes.note_id, 
contact_posts.why_post, contact_posts.type, contact_posts.post_id
FROM contacts, user_accounts, contact_notes, contact_posts
WHERE (contacts.system_id = '$sid' AND contacts.contact_id = 
user_accounts.system_id AND contact_notes.user_allowed = '$everybody' AND   
contact_posts.user_allowed = '$everybody') OR (contacts.contact_id = '$sid' 
AND contacts.system_id = user_accounts.system_id AND contact_notes.user_allowed 
= '$everybody' AND contact_posts.user_allowed = '$everybody')
LIMIT $startrow, 20";

$query = mysql_query($sql) or die ("Error: ".mysql_error());

$result = mysql_query($sql);

if ($result == "")
{
echo "";
}
echo "";

$rows = mysql_num_rows($result);

if($rows == 0)
{
print("");

}
elseif($rows > 0)
{
while($row = mysql_fetch_array($query))
{

$noteid = htmlspecialchars($row['note_id']);
$note_title = htmlspecialchars($row['note_name']);
$postid = htmlspecialchars($row['post_id']);
$postreason = htmlspecialchars($row['why_post']);
$datetimeadded = htmlspecialchars($row['just_date']);

print("<br /> <br />$note_title - $noteid <br /><br />$postreason - $postid");
}

}

Answer 1:

而不是使用mysql_fetch_array()使用mysql_fetch_assoc() 默认情况下, mysql_fetch_array()将返回与两个关联数量指标,这将导致你看到两次结果的阵列。



文章来源: How to prevent this query from printing same results twice?