Fastest way to multiply an array of int64_t?

I want to vectorize the multiplication of two memory aligned arrays. I didn't find any way to multiply 64*64 bit in AVX/AVX2, so I just did loop-unroll and AVX2 loads/stores. Is there a faster way to do this?

Note: I don't want to save the high-half result of each multiplication.

void multiply_vex(long *Gi_vec, long q, long *Gj_vec){

    int i;
    __m256i data_j, data_i;
    __uint64_t *ptr_J = (__uint64_t*)&data_j;
    __uint64_t *ptr_I = (__uint64_t*)&data_i;


    for (i=0; i<BASE_VEX_STOP; i+=4) {
        data_i = _mm256_load_si256((__m256i*)&Gi_vec[i]);
        data_j = _mm256_load_si256((__m256i*)&Gj_vec[i]);

        ptr_I[0] -= ptr_J[0] * q;
        ptr_I[1] -= ptr_J[1] * q;
        ptr_I[2] -= ptr_J[2] * q;
        ptr_I[3] -= ptr_J[3] * q;

        _mm256_store_si256((__m256i*)&Gi_vec[i], data_i);
    }


    for (; i<BASE_DIMENSION; i++)
        Gi_vec[i] -= Gj_vec[i] * q;
}

UPDATE: I'm using the Haswell microarchitecture with both ICC/GCC compilers. So both AVX and AVX2 is fine. I substitute the -= by the C intrisic _mm256_sub_epi64 after the multiplication loop-unroll, where it get some speedup. Currently, it is ptr_J[0] *= q; ...

I use __uint64_t but is a error. The right data type is __int64_t.

回答1:

You seem to be assuming long is 64bits in your code, but then using __uint64_t as well. In 32bit, the x32 ABI, and on Windows, long is a 32bit type. Your title mentions long long, but then your code ignores it. I was wondering for a while if your code was assuming that long was 32bit.

You're completely shooting yourself in the foot by using AVX256 loads but then aliasing a pointer onto the __m256i to do scalar operations. gcc just gives up and gives you the terrible code you asked for: vector load and then a bunch of extract and insert instructions. Your way of writing it means that both vectors have to be unpacked to do the sub in scalar as well, instead of using vpsubq.

Modern x86 CPUs have very fast L1 cache that can handle two operations per clock. (Haswell and later: two loads and one store per clock). Doing multiple scalar loads from the same cache line is better than a vector load and unpacking. (Imperfect uop scheduling reduces the throughput to about 84% of that, though: see below)

gcc 5.3 -O3 -march=haswell (Godbolt compiler explorer) auto-vectorizes a simple scalar implementation pretty well. When AVX2 isn't available, gcc foolishly still auto-vectorizes with 128b vectors: On Haswell, this will actually be about 1/2 the speed of ideal scalar 64bit code. (See the perf analysis below, but substitute 2 elements per vector instead of 4).

#include <stdint.h>    // why not use this like a normal person?
#define BASE_VEX_STOP 1024
#define BASE_DIMENSION 1028

// restrict lets the compiler know the arrays don't overlap,
// so it doesn't have to generate a scalar fallback case
void multiply_simple(uint64_t *restrict Gi_vec, uint64_t q, const uint64_t *restrict Gj_vec){
    for (intptr_t i=0; i<BASE_DIMENSION; i++)   // gcc doesn't manage to optimize away the sign-extension from 32bit to pointer-size in the scalar epilogue to handle the last less-than-a-vector elements
        Gi_vec[i] -= Gj_vec[i] * q;
}

inner loop:

.L4:
    vmovdqu ymm1, YMMWORD PTR [r9+rax]        # MEM[base: vectp_Gj_vec.22_86, index: ivtmp.32_76, offset: 0B], MEM[base: vectp_Gj_vec.22_86, index: ivtmp.32_76, offset: 0B]
    add     rcx, 1    # ivtmp.30,
    vpsrlq  ymm0, ymm1, 32      # tmp174, MEM[base: vectp_Gj_vec.22_86, index: ivtmp.32_76, offset: 0B],
    vpmuludq        ymm2, ymm1, ymm3        # tmp173, MEM[base: vectp_Gj_vec.22_86, index: ivtmp.32_76, offset: 0B], vect_cst_.25
    vpmuludq        ymm0, ymm0, ymm3        # tmp176, tmp174, vect_cst_.25
    vpmuludq        ymm1, ymm4, ymm1        # tmp177, tmp185, MEM[base: vectp_Gj_vec.22_86, index: ivtmp.32_76, offset: 0B]
    vpaddq  ymm0, ymm0, ymm1    # tmp176, tmp176, tmp177
    vmovdqa ymm1, YMMWORD PTR [r8+rax]        # MEM[base: vectp_Gi_vec.19_81, index: ivtmp.32_76, offset: 0B], MEM[base: vectp_Gi_vec.19_81, index: ivtmp.32_76, offset: 0B]
    vpsllq  ymm0, ymm0, 32      # tmp176, tmp176,
    vpaddq  ymm0, ymm2, ymm0    # vect__13.24, tmp173, tmp176
    vpsubq  ymm0, ymm1, ymm0    # vect__14.26, MEM[base: vectp_Gi_vec.19_81, index: ivtmp.32_76, offset: 0B], vect__13.24
    vmovdqa YMMWORD PTR [r8+rax], ymm0        # MEM[base: vectp_Gi_vec.19_81, index: ivtmp.32_76, offset: 0B], vect__14.26
    add     rax, 32   # ivtmp.32,
    cmp     rcx, r10  # ivtmp.30, bnd.14
    jb      .L4 #,

Translate that back to intrinsics if you want, but it's going to be a lot easier to just let the compiler autovectorize. I didn't try to analyse it to see if it's optimal.

If you don't usually compile with -O3, you could use #pragma omp simd before the loop (and -fopenmp).

Of course, instead of a scalar epilogue, it would prob. be faster to do an unaligned load of the last 32B of Gj_vec, and store into the last 32B of Gi_vec, potentially overlapping with the last store from the loop. (A scalar fallback is still needed if the arrays are smaller than 32B.)

Improved vector intrinsic version for Haswell

From my comments on Z Boson's answer. Based on Agner Fog's vector class library code.

Agner Fog's version saves an instruction but bottlenecks on the shuffle port by using phadd + pshufd where I use psrlq / paddq / pand.

Since one of your operands is constant, make sure to pass set1(q) as b, not a, so the "bswap" shuffle can be hoisted.

// replace hadd -> shuffle (4 uops) with shift/add/and (3 uops)
// The constant takes 2 insns to generate outside a loop.
__m256i mul64_haswell (__m256i a, __m256i b) {
    // instruction does not exist. Split into 32-bit multiplies
    __m256i bswap   = _mm256_shuffle_epi32(b,0xB1);           // swap H<->L
    __m256i prodlh  = _mm256_mullo_epi32(a,bswap);            // 32 bit L*H products

    // or use pshufb instead of psrlq to reduce port0 pressure on Haswell
    __m256i prodlh2 = _mm256_srli_epi64(prodlh, 32);          // 0  , a0Hb0L,          0, a1Hb1L
    __m256i prodlh3 = _mm256_add_epi32(prodlh2, prodlh);      // xxx, a0Lb0H+a0Hb0L, xxx, a1Lb1H+a1Hb1L
    __m256i prodlh4 = _mm256_and_si256(prodlh3, _mm256_set1_epi64x(0x00000000FFFFFFFF)); // zero high halves

    __m256i prodll  = _mm256_mul_epu32(a,b);                  // a0Lb0L,a1Lb1L, 64 bit unsigned products
    __m256i prod    = _mm256_add_epi64(prodll,prodlh4);       // a0Lb0L+(a0Lb0H+a0Hb0L)<<32, a1Lb1L+(a1Lb1H+a1Hb1L)<<32
    return  prod;
}

See it on Godbolt.

Note that this doesn't include the final subtract, only the multiply.

This version should perform a bit better on Haswell than gcc's autovectorized version. (like maybe one vector per 4 cycles instead of one vector per 5 cycles, bottlenecked on port0 throughput. I didn't consider other bottlenecks for the full problem, since this was a late addition to the answer.)

An AVX1 version (two elements per vector) would suck, and probably still be worse than 64bit scalar. Don't do it unless you already have your data in vectors, and want the result in a vector (extracting to scalar and back might not be worth it).

Perf analysis of GCC's autovectorized code (not the intrinsic version)

Background: see Agner Fog's insn tables and microarch guide, and other links in the x86 tag wiki.

Until AVX512 (see below), this is probably only barely faster than scalar 64bit code: imul r64, m64 has a throughput of one per clock on Intel CPUs (but one per 4 clocks on AMD Bulldozer-family). load/imul/sub-with-memory-dest is 4 fused-domain uops on Intel CPUs (with an addressing mode that can micro-fuse, which gcc fails to use). The pipeline width is 4 fused-domain uops per clock, so even a large unroll can't get this to issue at one-per-clock. With enough unrolling, we'll bottleneck on load/store throughput. 2 loads and one store per clock is possible on Haswell, but stores-address uops stealing load ports will lower the throughput to about 81/96 = 84% of that, according to Intel's manual.

So perhaps the best way for Haswell would load and multiply with scalar, (2 uops), then vmovq / pinsrq / vinserti128 so you can do the subtract with a vpsubq. That's 8 uops to load&multiply all 4 scalars, 7 shuffle uops to get the data into a __m256i (2 (movq) + 4 (pinsrq is 2 uops) + 1 vinserti128), and 3 more uops to do a vector load / vpsubq / vector store. So that's 18 fused-domain uops per 4 multiplies (4.5 cycles to issue), but 7 shuffle uops (7 cycles to execute). So nvm, this is no good compared to pure scalar.

The autovectorized code is using 8 vector ALU instructions for each vector of four values. On Haswell, 5 of those uops (multiplies and shifts) can only run on port 0, so no matter how you unroll this algorithm it will achieve at best one vector per 5 cycles (i.e. one multiply per 5/4 cycles.)

The shifts could be replaced with pshufb (port 5) to move the data and shift in zeros. (Other shuffles don't support zeroing instead of copying a byte from the input, and there aren't any known-zeros in the input that we could copy.)

paddq / psubq can run on ports 1/5 on Haswell, or p015 on Skylake.

Skylake runs pmuludq and immediate-count vector shifts on on p01, so it could in theory manage a throughput of one vector per max(5/2, 8/3, 11/4) = 11/4 = 2.75 cycles. So it bottlenecks on total fused-domain uop throughput (including the 2 vector loads and 1 vector store). So a bit of loop unrolling will help. Probably resource conflicts from imperfect scheduling will bottleneck it to slightly less than 4 fused-domain uops per clock. The loop overhead can hopefully run on port 6, which can only handle some scalar ops, including add and compare-and-branch, leaving ports 0/1/5 for vector ALU ops, since they're close to saturating (8/3 = 2.666 clocks). The load/store ports are nowhere near saturating, though.

So, Skylake can theoretically manage one vector per 2.75 cycles (plus loop overhead), or one multiply per ~0.7 cycles, vs. Haswell's best option (one per ~1.2 cycles in theory with scalar, or one per 1.25 cycles in theory with vectors). The scalar one per ~1.2 cycles would probably require a hand-tuned asm loop, though, because compilers don't know how to use a one-register addressing mode for stores, and a two-register addressing mode for loads (dst + (src-dst) and increment dst).

Also, if your data isn't hot in L1 cache, getting the job done with fewer instructions lets the frontend get ahead of the execution units, and get started on the loads before the data is needed. Hardware prefetch doesn't cross page lines, so a vector loop will probably beat scalar in practice for large arrays, and maybe even for smaller arrays.

AVX-512DQ introduces a 64bx64b->64b vector multiply

gcc can auto-vectorize using it, if you add -mavx512dq.

.L4:
    vmovdqu64       zmm0, ZMMWORD PTR [r8+rax]    # vect__11.23, MEM[base: vectp_Gj_vec.22_86, index: ivtmp.32_76, offset: 0B]
    add     rcx, 1    # ivtmp.30,
    vpmullq zmm1, zmm0, zmm2  # vect__13.24, vect__11.23, vect_cst_.25
    vmovdqa64       zmm0, ZMMWORD PTR [r9+rax]    # MEM[base: vectp_Gi_vec.19_81, index: ivtmp.32_76, offset: 0B], MEM[base: vectp_Gi_vec.19_81, index: ivtmp.32_76, offset: 0B]
    vpsubq  zmm0, zmm0, zmm1    # vect__14.26, MEM[base: vectp_Gi_vec.19_81, index: ivtmp.32_76, offset: 0B], vect__13.24
    vmovdqa64       ZMMWORD PTR [r9+rax], zmm0    # MEM[base: vectp_Gi_vec.19_81, index: ivtmp.32_76, offset: 0B], vect__14.26
    add     rax, 64   # ivtmp.32,
    cmp     rcx, r10  # ivtmp.30, bnd.14
    jb      .L4 #,

So AVX512DQ (expected to be part of Skylake multi-socket Xeon (Purley) in ~2017) will give a much larger than 2x speedup (from wider vectors) if these instructions are pipelined at one per clock.

Update: Skylake-AVX512 (aka SKL-X or SKL-SP) runs VPMULLQ at one per 1.5 cycles for xmm, ymm, or zmm vectors. It's 3 uops with 15c latency. (With maybe an extra 1c of latency for the zmm version, if that's not a measurement glitch in the AIDA results.)

vpmullq is much faster than anything you can build out of 32-bit chunks, so it's very much worth having an instruction for this even if current CPUs don't have 64-bit-element vector-multiply hardware. (Presumably they use the mantissa multipliers in the FMA units.)

回答2:

If you're interested in SIMD 64bx64b to 64b (lower) operations here are the AVX and AVX2 solutions from Agner Fog's Vector Class Library. I would test these with arrays and see how it compares to what GCC does with a generic loop such as the one in Peter Cordes' answer.

AVX (use SSE - you can still compile with -mavx to get vex encoding).

// vector operator * : multiply element by element
static inline Vec2q operator * (Vec2q const & a, Vec2q const & b) {
#if INSTRSET >= 5   // SSE4.1 supported
    // instruction does not exist. Split into 32-bit multiplies
    __m128i bswap   = _mm_shuffle_epi32(b,0xB1);           // b0H,b0L,b1H,b1L (swap H<->L)
    __m128i prodlh  = _mm_mullo_epi32(a,bswap);            // a0Lb0H,a0Hb0L,a1Lb1H,a1Hb1L, 32 bit L*H products
    __m128i zero    = _mm_setzero_si128();                 // 0
    __m128i prodlh2 = _mm_hadd_epi32(prodlh,zero);         // a0Lb0H+a0Hb0L,a1Lb1H+a1Hb1L,0,0
    __m128i prodlh3 = _mm_shuffle_epi32(prodlh2,0x73);     // 0, a0Lb0H+a0Hb0L, 0, a1Lb1H+a1Hb1L
    __m128i prodll  = _mm_mul_epu32(a,b);                  // a0Lb0L,a1Lb1L, 64 bit unsigned products
    __m128i prod    = _mm_add_epi64(prodll,prodlh3);       // a0Lb0L+(a0Lb0H+a0Hb0L)<<32, a1Lb1L+(a1Lb1H+a1Hb1L)<<32
    return  prod;
#else               // SSE2
    int64_t aa[2], bb[2];
    a.store(aa);                                           // split into elements
    b.store(bb);
    return Vec2q(aa[0]*bb[0], aa[1]*bb[1]);                // multiply elements separetely
#endif
}

AVX2

// vector operator * : multiply element by element
static inline Vec4q operator * (Vec4q const & a, Vec4q const & b) {
    // instruction does not exist. Split into 32-bit multiplies
    __m256i bswap   = _mm256_shuffle_epi32(b,0xB1);           // swap H<->L
    __m256i prodlh  = _mm256_mullo_epi32(a,bswap);            // 32 bit L*H products
    __m256i zero    = _mm256_setzero_si256();                 // 0
    __m256i prodlh2 = _mm256_hadd_epi32(prodlh,zero);         // a0Lb0H+a0Hb0L,a1Lb1H+a1Hb1L,0,0
    __m256i prodlh3 = _mm256_shuffle_epi32(prodlh2,0x73);     // 0, a0Lb0H+a0Hb0L, 0, a1Lb1H+a1Hb1L
    __m256i prodll  = _mm256_mul_epu32(a,b);                  // a0Lb0L,a1Lb1L, 64 bit unsigned products
    __m256i prod    = _mm256_add_epi64(prodll,prodlh3);       // a0Lb0L+(a0Lb0H+a0Hb0L)<<32, a1Lb1L+(a1Lb1H+a1Hb1L)<<32
    return  prod;
}

These functions work for signed and unsigned 64-bit integers. In your case since q is constant within the loop you don't need to recalculate some things every iteration but your compiler will probably figure that out anyway.