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问题:
I'm writing a spec for a controller in Rails 3 project using RSpec and Capybara, and I want to select current date from a select box. I tried:
select Date.today, :from => 'Date of birth'
but the spec fails and I get error:
Failure/Error: select Date.today, :from => 'Date of birth'
NoMethodError:
undefined method `to_xpath' for Mon, 18 Jul 2011:Date
How to fix it?
P.S. In view file I use simple_form_for tag and the select box is generated by code:
f.input :date_of_birth
回答1:
You need to specify the exact value as it's in the select menu in html. So if your select has values like "2011/01/01" then you need to write:
select '2011/01/01', :from => 'Date of birth'
Your code fails because you pass a date object.
回答2:
Had the same problem. I googled at lot and solved it this way:
Wrote date select macros into /spec/request_macros.rb
The select_by_id method is necessary for me, because the month is dependent on the translation
module RequestMacros
def select_by_id(id, options = {})
field = options[:from]
option_xpath = "//*[@id='#{field}']/option[#{id}]"
option_text = find(:xpath, option_xpath).text
select option_text, :from => field
end
def select_date(date, options = {})
field = options[:from]
select date.year.to_s, :from => "#{field}_1i"
select_by_id date.month, :from => "#{field}_2i"
select date.day.to_s, :from => "#{field}_3i"
end
end
Added them to my /spec/spec_helper.rb
config.include RequestMacros, :type => :request
Now in my integration tests in spec/requests i can use
select_date attr[:birthday], :from => "user_birthday"
Thanks to http://jasonneylon.wordpress.com/2011/02/16/selecting-from-a-dropdown-generically-with-capybara/ and https://gist.github.com/558786 :)
回答3:
with credit to Markus Hartmair for an excellent solution, I prefer to use labels as selectors because of improved readability. So my version of his helper module is:
module SelectDateHelper
def select_date(date, options = {})
field = options[:from]
base_id = find(:xpath, ".//label[contains(.,'#{field}')]")[:for]
year, month, day = date.split(',')
select year, :from => "#{base_id}_1i"
select month, :from => "#{base_id}_2i"
select day, :from => "#{base_id}_3i"
end
end
call it like this:
select_date "2012,Jan,1", :from => "From date"
回答4:
A slight adaption of Markus's answer:
def select_date(date, options = {})
raise ArgumentError, 'from is a required option' if options[:from].blank?
field = options[:from].to_s
select date.year.to_s, :from => "#{field}_1i"
select Date::MONTHNAMES[date.month], :from => "#{field}_2i"
select date.day.to_s, :from => "#{field}_3i"
end
回答5:
I found a clean solution for rspec and capybara to test using date and time select methods, where in your HTML you use a datetime select or date select. This works with Rails 4, RSpec 3.1 and Capybara 2.4.4.
Say in your HTML form you have the following:
<%= f.datetime_select(:start_date, {default: DateTime.now, prompt: {day: 'Choose day', month: "Choose month", year: "Choose year"}}, {class: "date-select"}) %>
the DateTime Select View helper will create 5 select fields with ids such as id="modelname_start_date_1i"
, where the id the is appended with 1i, 2i, 3i, 4i, 5i. By default Year, Month, Day, Hour, Minute. If you change the order of the fields, make sure to change the feature helper below.
1) Create a Feature Helper for dates and times helpers
spec/support/helpers/date_time_select_helpers.rb
module Features
module DateTimeSelectHelpers
def select_date_and_time(date, options = {})
field = options[:from]
select date.strftime('%Y'), :from => "#{field}_1i" #year
select date.strftime('%B'), :from => "#{field}_2i" #month
select date.strftime('%-d'), :from => "#{field}_3i" #day
select date.strftime('%H'), :from => "#{field}_4i" #hour
select date.strftime('%M'), :from => "#{field}_5i" #minute
end
def select_date(date, options = {})
field = options[:from]
select date.strftime('%Y'), :from => "#{field}_1i" #year
select date.strftime('%B'), :from => "#{field}_2i" #month
select date.strftime('%-d'), :from => "#{field}_3i" #day
end
end
end
Note that for the day I use %-d
that gives you a non-padded numeric value (i.e. 4) instead of %d
that has a zero-padded numeric value (i.e. 04). Check the date formats with strftime
2) You then need to include your date and time helpers methods in spec/support/helpers.rb so you can use them in any spec file.
require 'support/helpers/date_time_select_helpers'
RSpec.configure do |config|
config.include Features::DateTimeSelectHelpers, type: :feature
end
3) In your Spec file you can call your helper. For example:
feature 'New Post' do
scenario 'Add a post' do
visit new_post_path
fill_in "post[name]", with: "My post"
select_date_and_time(2.days.from_now, from:"post_start_date")
click_button "Submit"
expect(page).to have_content "Your post was successfully saved"
end
end
回答6:
Thanks to Dylan for pointing it out, but in case anyone is looking for the cucumber version, you can use this:
select_date("Date of birth", :with => "1/1/2011")
For more information, see select_date.
回答7:
Given the following Formtastic code renders Rails default date selector:
= f.input :born_on, end_year: Time.now.year, start_year: 60.years.ago.year
In your spec, break the date into separate calls to each individual select tag:
select '1956', from: 'person_born_on_1i'
select 'July', from: 'person_born_on_2i'
select '9', from: 'person_born_on_3i'
I don't like that this code is so aware of the HTML, but it does work with the versions of gems at this time.
Gems:
- Capybara 2.1.0
- Formtastic 2.2.1
- Rails 3.2.13
- RSpec 2.13.0
回答8:
In my particular situation, I'm adding potentially multiple date select fields to the page with accepts_nested_attributes_for
functionality. This means, I'm not sure what the full id
or name
of the fields are going to be.
Here's the solution I came up with in case it helps anyone else Googling this:
I'm wrapping the date select field in a container div with a class:
<div class='date-of-birth-container'>
<%= f.date_select :date_of_birth %>
</div>
Then in my feature spec:
within '.date-of-birth-container' do
find("option[value='1']", text: 'January').select_option
find("option[value='1']", text: '1').select_option
find("option[value='1955']").select_option
end
Here's a helper method I wrote for it:
def select_date_within_css_selector(date, css_selector)
month_name = Date::MONTHNAMES.fetch(date.month)
within css_selector do
find("option[value='#{date.month}']", text: month_name).select_option
find("option[value='#{date.day}']", text: date.day.to_s).select_option
find("option[value='#{date.year}']").select_option
end
end
Then using the helper:
select_date_within_css_selector(Date.new(1955, 1, 1), '.date-of-birth-container')
回答9:
The following worked for me, using a date_field:
fill_in "Date", with: DateTime.now.strftime('%m/%d/%Y')
回答10:
For Rails 4, in case somebody gets to this question without being limited to Rails 3.
select '2020', from: 'field_name_{}_1i'
select 'January', from: 'field_name_{}_2i'
select '1', from: 'field_name_{}_3i'
You can of course extract this to a helper and make it dynamic.
回答11:
It looks like this one has been sufficiently covered, but see Capybara's docs for an official answer. You can select by name, id, or label text.