有什么不对的HQL? “节点无数据类型”(What's wrong with this

2019-07-28 22:20发布

session.createQuery("Select attribute from GoodsSection tgs " +
    "join gs.ascendants ags join ags.attributes attribute " +
    "where attribute.outerId = :outerId and tgs = :section ")
.setString("outerId", pOuterId)
.setEntity("section", section)
.setMaxResults(1)
.uniqueResult();

看起来好像没什么问题,但结果是

java.lang.IllegalStateException: No data type for node: org.hibernate.hql.ast.tree.IdentNode 
 \-[IDENT] IdentNode: 'attribute' {originalText=attribute}

    at org.hibernate.hql.ast.tree.SelectClause.initializeExplicitSelectClause(SelectClause.java:145)
    at org.hibernate.hql.ast.HqlSqlWalker.useSelectClause(HqlSqlWalker.java:705)
    at org.hibernate.hql.ast.HqlSqlWalker.processQuery(HqlSqlWalker.java:529)
    at org.hibernate.hql.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:645)
    at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:281)
    at org.hibernate.hql.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:229)

为什么? 怎么了?

Answer 1:

您还没有明确了“GS”的别名。 你只需要“AG”与“TGS”。



文章来源: What's wrong with this HQL? “No data type for node”