I want to run a method I know this method doesn't work and I want to get the error returned by the method.
This is my code :
def is_connect(s):
print("ok connection")
print(s)
ioloop.stop()
try:
current_job_ready = 0
print("ok1")
beanstalk = beanstalkt.Client(host='host', port=port)
print("ok1")
beanstalk.connect(callback=is_connect)
ioloop = tornado.ioloop.IOLoop.instance()
ioloop.start()
print("ok2")
except IOError as e:
print(e)
And this is the error I have when I run my program with wring port :
WARNING:tornado.general:Connect error on fd 7: ECONNREFUSED
ERROR:tornado.application:Exception in callback <functools.partial object at 0x7f5a0eac6f18>
Traceback (most recent call last):
File "/usr/local/lib/python2.7/dist-packages/tornado/ioloop.py", line 604, in _run_callback
ret = callback()
File "/usr/local/lib/python2.7/dist-packages/tornado/stack_context.py", line 275, in null_wrapper
return fn(*args, **kwargs)
File "/usr/local/lib/python2.7/dist-packages/tornado/ioloop.py", line 619, in <lambda>
self.add_future(ret, lambda f: f.result())
File "/usr/local/lib/python2.7/dist-packages/tornado/concurrent.py", line 237, in result
raise_exc_info(self._exc_info)
File "/usr/local/lib/python2.7/dist-packages/tornado/gen.py", line 270, in wrapper
result = func(*args, **kwargs)
TypeError: connect() takes exactly 1 argument (2 given)
I want to have e when I enter a false port or host.
How can I do this?
I tired to add raise IOError("connection error")
after beanstalk = beanstalkt.Client(host='host', port=port)
But this force the error, and I just want to have error when it exist.