I have a table that is made by ngRepeat from variable first. By filter, instead of first.id_second it writes out second.name, and it works great. Now I'm trying to sort the column first.id_second and I want it to be sorted not by first.id_second, but by second.name. This is my structure:
var first = [{
"id": 0,
"id_second": "111"
},{
"id": 1,
"id_second": "222"
}]
var second = [{
"id_second": "111",
"name": "name1"
},{
"id_second": "222",
"name": "name2"
}]
Usually, in my html I would have
ng-click="order('col_name')"
And in controller
$scope.order = function(predicate) {
$scope.predicate = predicate;
$scope.reverse = ($scope.predicate === predicate) ? !$scope.reverse : false;
$scope.first = orderBy($scope.first, predicate, $scope.reverse);
};
var orderBy = $filter('orderBy');
I don't know how to filter by a property that is from another variable. I suppose I should write a custom filter, but so far wasn't succesfull in it.
Any ideas? Thanx.
It seems that there is no way to do this simple, so in the end I wrote a custom orderBy function in which I implemented quicksort.
// arranging data from second to get to the data easier
var secondKeyVal = {};
for (var i = 0; i < $scope.second.length; i++) {
secondKeyVal[$scope.second[i].id_second] = $scope.second[i].naziv;
}
// function that is called from html
$scope.orderByCustom = function(predicate) {
$scope.predicate = predicate;
$scope.reverse = ($scope.predicate === predicate) ? !$scope.reverse : false;
$scope.orderByCustomSort();
};
$scope.orderByCustomSort= function() {
var sorted = quickSort($scope.first);
$scope.first = sorted;
};
function quickSort(a) {
if (a.length <= 1) return a;
var left=[], right=[], pivot=secondKeyVal[a[0].id_second];
for (var i = 1; i < a.length; i++) {
secondKeyVal[a[i].id_second] <= pivot ? left.push(a[i]) : right.push(a[i]);
}
return quickSort(left).concat(a[0], quickSort(right));
}
Ofcourse, if anyone manages to pull this out without using additional libraries that would make me have to change html filters and orderBy I already use, it would be most welcome :)