How can i check if a $string
contains any of the items expressed in an array?
$string = 'My nAmE is Tom.';
$array = array("name","tom");
if(contains($string,$array))
{
// do something to say it contains
}
Any ideas?
How can i check if a $string
contains any of the items expressed in an array?
$string = 'My nAmE is Tom.';
$array = array("name","tom");
if(contains($string,$array))
{
// do something to say it contains
}
Any ideas?
is that what you wanted? i hope that code is compiling :)
$string = 'My nAmE is Tom.';
$array = array("name","tom");
if(0 < count(array_intersect(array_map('strtolower', explode(' ', $string)), $array)))
{
//do sth
}
I don't think there is a built-in function that will handle what you want. You could easily write a contains()
function however:
function contains($str, array $arr)
{
foreach($arr as $a) {
if (stripos($str,$a) !== false) return true;
}
return false;
}
Using the accepted answer:
$string = 'My nAmE is Tom.';
$array = array("name","tom");
if(0 < count(array_intersect(array_map('strtolower', explode(' ', $string)), $array)))
{
//do sth
}
Just a side note that the if statement could be changed to:
if(0 < count(array_intersect(explode(' ', strtolower($string)), $array)))
since it's not really necessary to use array_map to apply strtolower
to each element. instead apply it to the initial string.
One more workaround for contains function
function contains($string, $array, $caseSensitive = true)
{
$stripedString = $caseSensitive ? str_replace($array, '', $string) : str_ireplace($array, '', $string);
return strlen($stripedString) !== strlen($string);
}
PS. as for me, I'm just use it without function..
if (strlen(str_replace($array, '', $string)) !== strlen($string)) {
// do it
}
Something like this would work:
$string = 'My nAmE is Tom.';
$array = array("name", "tom");
foreach ($array as $token) {
if (stristr($string, $token) !== FALSE) {
print "String contains: $token\n";
}
}
<?php
$input = preg_quote('blu', '~'); // don't forget to quote input string!
$data = array('orange', 'blue', 'green', 'red', 'pink', 'brown', 'black');
$result = preg_grep('~' . $input . '~', $data);
print_r($result);
?>
Will this do the job?
$words = explode(" ", $string);
$wordsInArray = array();
foreach($words as $word) {
if(in_array($word, $array)) {
$wordsInArray[] = $word;
}
}
function contains($str, $arr)
{
$ptn = '';
foreach ($arr as $s) {
if ($ptn != '') $ptn .= '|';
$ptn .= preg_quote($s, '/');
}
return preg_match("/$ptn/i", $str);
}
echo contains('My nAmE is Tom', array('name', 'tom'));
Another way to do with array_intersect() function, Try below code :
function checkString(array $arr, $str) {
$str = preg_replace( array('/[^ \w]+/', '/\s+/'), ' ', strtolower($str) ); // Remove Special Characters and extra spaces -or- convert to LowerCase
$matchedString = array_intersect( explode(' ', $str), $arr);
if ( count($matchedString) > 0 ) {
return true;
}
return false;
}
Much simpler, please refer the link in_array
$os = array("Mac", "NT", "Irix", "Linux");
if (in_array("Irix", $os)) {
echo "Es Irix";
}