Test for non-zero length string in Bash: [ -n “$va

问题:

I've seen bash scripts test for non-zero length string in two different ways. Most scripts use the -n option:

#!/bin/bash
# With the -n option
if [ -n "$var" ]; then
  # Do something when var is non-zero length
fi

But the -n option isn't really needed:

# Without the -n option
if [ "$var" ]; then
  # Do something when var is non-zero length
fi

Which is the better way?

Similarly, which is the better way for testing for zero-length:

if [ -z "$var" ]; then
  # Do something when var is zero-length
fi

or

if [ ! "$var" ]; then
  # Do something when var is zero-length
fi

回答1:

Edit: This is a more complete version that shows more differences between [ (aka test) and [[.

The following table shows that whether a variable is quoted or not, whether you use single or double brackets and whether the variable contains only a space are the things that affect whether using a test with or without -n/-z is suitable for checking a variable.

       1a    2a    3a    4a    5a    6a    |1b    2b    3b    4b    5b    6b
       [     ["    [-n   [-n"  [-z   [-z"  |[[    [["   [[-n  [[-n" [[-z  [[-z"
unset: false false true  false true  true  |false false false false true  true
null : false false true  false true  true  |false false false false true  true
space: false true  true  true  true  false |true  true  true  true  false false
zero : true  true  true  true  false false |true  true  true  true  false false
digit: true  true  true  true  false false |true  true  true  true  false false
char : true  true  true  true  false false |true  true  true  true  false false
hyphn: true  true  true  true  false false |true  true  true  true  false false
two  : -err- true  -err- true  -err- false |true  true  true  true  false false
part : -err- true  -err- true  -err- false |true  true  true  true  false false
Tstr : true  true  -err- true  -err- false |true  true  true  true  false false
Fsym : false true  -err- true  -err- false |true  true  true  true  false false
T=   : true  true  -err- true  -err- false |true  true  true  true  false false
F=   : false true  -err- true  -err- false |true  true  true  true  false false
T!=  : true  true  -err- true  -err- false |true  true  true  true  false false
F!=  : false true  -err- true  -err- false |true  true  true  true  false false
Teq  : true  true  -err- true  -err- false |true  true  true  true  false false
Feq  : false true  -err- true  -err- false |true  true  true  true  false false
Tne  : true  true  -err- true  -err- false |true  true  true  true  false false
Fne  : false true  -err- true  -err- false |true  true  true  true  false false

If you want to know if a variable is non-zero length, do any of the following:

• quote the variable in single brackets (column 2a)
• use -n and quote the variable in single brackets (column 4a)
• use double brackets with or without quoting and with or without -n (columns 1b - 4b)

Notice in column 1a starting at the row labeled "two" that the result indicates that [ is evaluating the contents of the variable as if they were part of the conditional expression (the result matches the assertion implied by the "T" or "F" in the description column). When [[ is used (column 1b), the variable content is seen as a string and not evaluated.

The errors in columns 3a and 5a are caused by the fact that the variable value includes a space and the variable is unquoted. Again, as shown in columns 3b and 5b, [[ evaluates the variable's contents as a string.

If you're using [, the key to making sure that you don't get unexpected results is quoting the variable. Using [[, it doesn't matter.

The error messages, which are being suppressed, are "unary operator expected" or "binary operator expected".

This is the script that produced the table above.

#!/bin/bash
# by Dennis Williamson
# 2010-10-06, revised 2010-11-10
# for http://stackoverflow.com/questions/3869072/test-for-non-zero-length-string-in-bash-n-var-or-var
# designed to fit an 80 character terminal

dw=5    # description column width
w=6     # table column width

t () { printf "%-${w}s" "true"; }
f () { [[ $? == 1 ]] && printf "%-${w}s" "false " || printf "%-${w}s" "-err- "; }

o=/dev/null

echo '       1a    2a    3a    4a    5a    6a    |1b    2b    3b    4b    5b    6b'
echo '       [     ["    [-n   [-n"  [-z   [-z"  |[[    [["   [[-n  [[-n" [[-z  [[-z"'

while read -r d t
do
    printf "%-${dw}s: " "$d"

    case $d in
        unset) unset t  ;;
        space) t=' '    ;;
    esac

    [ $t ]        2>$o  && t || f
    [ "$t" ]            && t || f
    [ -n $t ]     2>$o  && t || f
    [ -n "$t" ]         && t || f
    [ -z $t ]     2>$o  && t || f
    [ -z "$t" ]         && t || f
    echo -n "|"
    [[ $t ]]            && t || f
    [[ "$t" ]]          && t || f
    [[ -n $t ]]         && t || f
    [[ -n "$t" ]]       && t || f
    [[ -z $t ]]         && t || f
    [[ -z "$t" ]]       && t || f
    echo

done <<'EOF'
unset
null
space
zero    0
digit   1
char    c
hyphn   -z
two     a b
part    a -a
Tstr    -n a
Fsym    -h .
T=      1 = 1
F=      1 = 2
T!=     1 != 2
F!=     1 != 1
Teq     1 -eq 1
Feq     1 -eq 2
Tne     1 -ne 2
Fne     1 -ne 1
EOF

回答2:

It is better to use the more powerful [[ as far as Bash is concerned.

Usual cases

if [[ $var ]]; then   # var is set and it is not empty
if [[ ! $var ]]; then # var is not set or it is set to an empty string

The above two constructs look clean and readable. They should suffice in most cases.

Note that we don't need to quote the variable expansions inside [[ as there is no danger of word splitting and globbing.

Rare cases

In the rare case of us having to make a distinction between "being set to an empty string" vs "not being set at all", we could use these:

if [[ ${var+x} ]]; then           # var is set but it could be empty
if [[ ! ${var+x} ]]; then         # var is not set
if [[ ${var+x} && ! $var ]]; then # var is set and is empty

We can also use the -v test:

if [[ -v var ]]; then             # var is set but it could be empty
if [[ ! -v var ]]; then           # var is not set
if [[ -v var && ! $var ]]; then   # var is set and is empty
if [[ -v var && -z var ]]; then   # var is set and is empty

---

Related posts and documentation

There are a plenty of posts related to this topic. Here are a few:

• How to check if a variable is set in Bash?
• How to check if an environment variable exists and get its value?
• How to find whether or not a variable is empty in Bash
• What does “plus colon” (“+:”) mean in shell script expressions?
• Is double square brackets [[ ]] preferable over single square brackets [ ] in Bash?
• What is the difference between single and double square brackets in Bash?
• An excellent answer by mklement0 where he talks about [[ vs [
• Bash Hackers Wiki - [ vs [[

回答3:

Here are some more tests

True if string is not empty:

[ -n "$var" ]
[[ -n $var ]]
test -n "$var"
[ "$var" ]
[[ $var ]]
(( ${#var} ))
let ${#var}
test "$var"

True if string is empty:

[ -z "$var" ]
[[ -z $var ]]
test -z "$var"
! [ "$var" ]
! [[ $var ]]
! (( ${#var} ))
! let ${#var}
! test "$var"

回答4:

use case/esac to test

case "$var" in
  "") echo "zero length";;
esac

回答5:

An alternative and perhaps more transparent way of evaluating an empty env variable is to use...

  if [ "x$ENV_VARIABLE" != "x" ] ; then
      echo 'ENV_VARIABLE contains something'
  fi

回答6:

The correct answer is the following:

if [[ -n $var ]] ; then
  blah
fi

Note the use of the [[...]], which correctly handles quoting the variables for you.