thrust::sequence - how to increase the step after

问题:

I am using

thrust::sequence(myvector.begin(), myvector.end(), 0, 1)

and achieve good ordered list like:

0, 1, 2, 3, 4

My question is how can I achieve such a list below (the best way?)

0, 0, 0, 1, 1, 1, 2, 2 ,2, 3, 3, 3

I know how to make it with functors, so please do not try to answer it with functor. I want to learn if there is an optimized way for it in Thrust, or am I missing a simple way..

回答1:

Something like this:

thrust::device_vector<int> myvector(N);

thrust::transform( thrust::make_counting_iterator(0),
                   thrust::make_counting_iterator(N),
                   thrust::make_constant_iterator(3),
                   myvector.begin(),
                   thrust::divides<int>() );

(disclaimer, written in browser, never compiled or tested, use at own risk)

should give you the sequence you are looking for by computing [0..N]//3 and outputting the result on myvector.

---

Seeing as you are having trouble compiling your version, here is a complete example which compiles and runs:

#include <thrust/device_vector.h>
#include <thrust/transform.h>
#include <thrust/functional.h>
#include <thrust/iterator/counting_iterator.h>
#include <thrust/iterator/constant_iterator.h>
#include <cstdio>

int main(void)
{
    const int N = 18, M = 3;
    thrust::device_vector<int> myvector(N);

    thrust::transform(  thrust::make_counting_iterator(0),
                        thrust::make_counting_iterator(N),
                        thrust::make_constant_iterator(M),
                        myvector.begin(),
                        thrust::divides<int>() );

    for(int i=0; i<N; i++) {
        int val = myvector[i];
        printf("%d %d\n", i, val);
    }
    return 0;
}