mysql_close() expects parameter 1 to be resource,

问题:

The line causing the error is this one...

mysql_close($con);

Here is the entirety of the code...

$con=mysqli_connect("localhost","root","pass","db_name");
// Check connection
if (mysqli_connect_errno()) {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

$result = mysqli_query($con,"SELECT * FROM medicos");


    while($row = mysqli_fetch_array($result)) {
    echo '.....';
    }



    mysql_close($con);

回答1:

The line mysql_close($con); must be changed to mysqli_close($con);

You cannot interchangeably use mysql and mysqli functions, for example:

mysqli_connect requires use of mysqli_close

- likewise -

mysql_connect requires use of mysql_close