How do I convert a struct to a byte array without

问题:

[StructLayout(LayoutKind.Explicit)]
public struct struct1
{
    [FieldOffset(0)]
        public byte a;   // 1 byte
    [FieldOffset(1)]
        public int b;    // 4 bytes
    [FieldOffset(5)]
        public short c;  // 2 bytes
    [FieldOffset(7)]
        public byte buffer;
    [FieldOffset(18)]
        public byte[] shaHashResult;   // 20 bytes
}

void DoStuff()
{
   struct1 myTest = new struct1();
   myTest.shaHashResult =  sha256.ComputeHash(pkBytes);  // 20 bytes

   byte[] newParameter = myTest.ToArray() //<-- How do I convert a struct 
                                          //     to array without a copy?
}

How do I take the array myTest and convert it to a byte[]? Since my objects will be large, I don't want to copy the array (memcopy, etc)

回答1:

Since you have a big array, this is really the only way you will be able to do what you want:

var myBigArray = new Byte[100000];

// ...

var offset = 0;
var hash = sha256.ComputeHash(pkBytes);
Buffer.BlockCopy(myBigArray, offset, hash, 0, hash.Length);

// if you are in a loop, do something like this
offset += hash.Length;

This code is very efficient, and even in a tight loop, the results of ComputeHash will be collected in a quick Gen0 collection, while myBigArray will be on the Large Object Heap, and not moved or collected. The Buffer.BlockCopy is highly optimized in the runtime, yielding the fastest copy you could probably achieve, even in the face of pinning the target, and using an unrolled pointer copy.