Is there a regex to replace the outer part of a string while keeping the inner part?
before:
${person.dog.name}
after:
<c:out value="${person.dog.name}"/>
I need to use it in Eclipse editor, and the inner part changes.
This can be useful too:
Search: \$\{(.*?)\}
Replace:\$\{fn:escapeXml\($1\)\}
${person.dog.name}
become
${fn:escapeXml(person.dog.name)}
Find expression with:
(\$\{[^\}]+\})
and replace expression will be:
<c:out value="$1"/>
To find ${person.dog.name} with <c:out value="${person.dog.name}"/> in Eclipse editor!
Edit:
Be careful while using it, because <c:if test="${foo}"> will end up like <c:if test="<c:out value="${foo}" />">
Just capture the entire string with ^(.*)$ and then use in the replace function use a back reference like <c:out value="$1"/> where the $1 is the backreference
string.replaceAll("^(.*)$", "<c:out value=\"$1\"/>")
In eclipse see link. You'd put ^(.*)$ into find, <c:out value="$1"/> into replace. select regular expressions, click find and replace.
If you're looking to capture all the ${foo} with <c:out value="${foo}"/>? in some larger text then you'll have to use the regex ([$]{foo}) to find all the desired text then use <c:out value=\"$1\"/> in the replace field.
